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  • Compare Version Numbers

    Compare two version numbers version1 and version2.
    If version1 > version2 return 1, if version1 < version2 return -1, otherwise return 0.

    You may assume that the version strings are non-empty and contain only digits and the . character.
    The . character does not represent a decimal point and is used to separate number sequences.
    For instance, 2.5 is not "two and a half" or "half way to version three", it is the fifth second-level revision of the second first-level revision.

    Here is an example of version numbers ordering:

    0.1 < 1.1 < 1.2 < 13.37
    public class Solution {
        public int compareVersion(String version1, String version2) {
            String[] levels1 = version1.split("\.");
            String[] levels2 = version2.split("\.");
        
            int length = Math.max(levels1.length, levels2.length);
            for (int i=0; i<length; i++) {
                Integer v1 = i < levels1.length ? Integer.parseInt(levels1[i]) : 0;
                Integer v2 = i < levels2.length ? Integer.parseInt(levels2[i]) : 0;
                int compare = v1.compareTo(v2);
                if (compare != 0) {
                    return compare;
                }
            }
        
            return 0;
        }
    }

    split: http://stackoverflow.com/questions/7935858/the-split-method-in-java-does-not-work-on-a-dot

    reference: https://leetcode.com/discuss/19118/accepted-small-java-solution

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  • 原文地址:https://www.cnblogs.com/hygeia/p/5469920.html
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