1.输入一个年份,判断是不是闰年(能被4整除但不能被100整除,或者能被400整除)
package com.a01;
import java.util.*;
public class hellowold {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("输入一个年份");
int a = input.nextInt();
if ((a % 4 == 0 && a % 100 != 0) || a % 400 == 0) {
System.out.println(a + "是闰年");
} else {
System.out.println(a + "不是闰年");
}
}
}
2.输入一个4位会员卡号,如果百位数字是3的倍数,就输出是幸运会员,否则就输出不是.
package com.a01;
import java.util.*;
public class hellowold {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("输入一个四位卡号");
int a = input.nextInt();
if (a / 100 % 10 % 3 == 0 && a / 100 % 10 != 0) {
System.out.println(a + "是幸运会员");
} else {
System.out.println(a + "不是");
}
}
}
3.已知函数,输入x的值,输出对应的y的值. x + 3 ( x > 0 ) y = 0 ( x = 0 ) x2 –1 ( x < 0 )
package com.a01;
import java.util.*;
public class hellowold {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("输入x的值");
int x = input.nextInt();
if (x > 0) {
System.out.println("y=" + (x + 3));
} else if (x == 0) {
System.out.println("y=" + x);
} else {
System.out.println("y=" + (x * 2 - 1));
}
}
}
4.输入三个数,判断能否构成三角形(任意两边之和大于第三边)
package com.a01;
import java.util.*;
public class hellowold {
public static void main(String[] args) {
Scanner input = new Scanner(System.in);
System.out.println("取3条边预构成一个三角形");
int a = input.nextInt();
int b = input.nextInt();
int c = input.nextInt();
if (a+b>c&&a+c>b&&b+c>a) {
System.out.println("这三条边能构成一个三角形");
} else {
System.out.println("不能构成三角形");
}
}
}
