zoukankan      html  css  js  c++  java
  • 201521123040《Java程序设计》第9周学习总结

    1. 本周学习总结

    1.1 以你喜欢的方式(思维导图或其他)归纳总结异常相关内容。

    2. 书面作业

    本次PTA作业题集异常

    1.常用异常

    题目5-1

    1.1 截图你的提交结果(出现学号)

    1.2 自己以前编写的代码中经常出现什么异常、需要捕获吗(为什么)?应如何避免?

    1.3 什么样的异常要求用户一定要使用捕获处理?

    2.处理异常使你的程序更加健壮

    题目5-2

    2.1 截图你的提交结果(出现学号)

    2.2 实验总结

    3.throw与throws

    题目5-3

    3.1 截图你的提交结果(出现学号)

    3.2 阅读Integer.parsetInt源代码,结合3.1说说抛出异常时需要传递给调用者一些什么信息?

    源代码

     public static int parseInt(String s, int radix)
                    throws NumberFormatException
        {
            /*
             * WARNING: This method may be invoked early during VM initialization
             * before IntegerCache is initialized. Care must be taken to not use
             * the valueOf method.
             */
    
            if (s == null) {
                throw new NumberFormatException("null");
            }
    
            if (radix < Character.MIN_RADIX) {
                throw new NumberFormatException("radix " + radix +
                                                " less than Character.MIN_RADIX");
            }
    
            if (radix > Character.MAX_RADIX) {
                throw new NumberFormatException("radix " + radix +
                                                " greater than Character.MAX_RADIX");
            }
    
            int result = 0;
            boolean negative = false;
            int i = 0, len = s.length();
            int limit = -Integer.MAX_VALUE;
            int multmin;
            int digit;
    
            if (len > 0) {
                char firstChar = s.charAt(0);
                if (firstChar < '0') { // Possible leading "+" or "-"
                    if (firstChar == '-') {
                        negative = true;
                        limit = Integer.MIN_VALUE;
                    } else if (firstChar != '+')
                        throw NumberFormatException.forInputString(s);
    
                    if (len == 1) // Cannot have lone "+" or "-"
                        throw NumberFormatException.forInputString(s);
                    i++;
                }
                multmin = limit / radix;
                while (i < len) {
                    // Accumulating negatively avoids surprises near MAX_VALUE
                    digit = Character.digit(s.charAt(i++),radix);
                    if (digit < 0) {
                        throw NumberFormatException.forInputString(s);
                    }
                    if (result < multmin) {
                        throw NumberFormatException.forInputString(s);
                    }
                    result *= radix;
                    if (result < limit + digit) {
                        throw NumberFormatException.forInputString(s);
                    }
                    result -= digit;
                }
            } else {
                throw NumberFormatException.forInputString(s);
            }
            return negative ? result : -result;
        }
    
        /**
         * Parses the string argument as a signed decimal integer. The
         * characters in the string must all be decimal digits, except
         * that the first character may be an ASCII minus sign {@code '-'}
         * ({@code 'u005Cu002D'}) to indicate a negative value or an
         * ASCII plus sign {@code '+'} ({@code 'u005Cu002B'}) to
         * indicate a positive value. The resulting integer value is
         * returned, exactly as if the argument and the radix 10 were
         * given as arguments to the {@link #parseInt(java.lang.String,
         * int)} method.
         *
         * @param s    a {@code String} containing the {@code int}
         *             representation to be parsed
         * @return     the integer value represented by the argument in decimal.
         * @exception  NumberFormatException  if the string does not contain a
         *               parsable integer.
         */
        public static int parseInt(String s) throws NumberFormatException {
            return parseInt(s,10);
        }
    
    

    4.函数题

    题目4-1(多种异常的捕获)

    3.1 截图你的提交结果(出现学号)

    3.2 一个try块中如果可能抛出多种异常,捕获时需要注意些什么?

    5.为如下代码加上异常处理

    byte[] content = null;
    FileInputStream fis = new FileInputStream("testfis.txt");
    int bytesAvailabe = fis.available();//获得该文件可用的字节数
    if(bytesAvailabe>0){
    content = new byte[bytesAvailabe];//创建可容纳文件大小的数组
    fis.read(content);//将文件内容读入数组
    }
    System.out.println(Arrays.toString(content));//打印数组内容

    5.1 改正代码,让其可正常运行。注1:里面有多个方法均可能抛出异常。注2:要使用finally关闭资源。

    5.2 使用Java7中的try-with-resources来改写上述代码实现自动关闭资源.

    3. 码云上代码提交记录

    题目集:异常

    3.1. 码云代码提交记录

    在码云的项目中,依次选择“统计-Commits历史-设置时间段”, 然后搜索并截图

  • 相关阅读:
    oracle权限配置
    oracle锁表处理
    小组成员
    个人项目 Individual Project
    Java单元测试框架 JUnit
    MyEclipse的快捷键大全(超级实用,方便)
    vs2008 连接 vss2005 出现 analyze utility 错误的解决方法
    EXTJS gridpanel 动态设置表头
    IE8不能上网的问题
    一些事件的评论
  • 原文地址:https://www.cnblogs.com/hyrrr/p/6746540.html
Copyright © 2011-2022 走看看