107. 987654321 problem
time limit per test: 0.25 sec.
memory limit per test: 4096
KB
For given number N you must output amount of N-digit numbers, such, that last digits of their square is equal to 987654321.
Input
Input contains integer number N (1<=N<=106)
Output
Write answer to the output.
Sample Input
8
Sample Output
0
打表可知当n == 9时有八个解,大于9的解由乘法原理易算
1 #include <iostream> 2 #include <cstdio> 3 #include <cstring> 4 #include <algorithm> 5 6 using namespace std; 7 8 int n; 9 int main() 10 { 11 12 scanf("%d",&n); 13 14 if( n <= 8 ) { 15 printf("0 "); 16 17 } else if(n == 9) { 18 printf("8 "); 19 } else { 20 printf("72"); 21 for(int i = 10; i < n; i++) { 22 printf("0 "); 23 } 24 } 25 return 0; 26 }