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  • OCP-1Z0-051-V9.02-149题

    149. View the Exhibits and examine the structures of the COSTS and PROMOTIONS tables.

    Evaluate the following SQL statement:

    SQL> SELECT prod_id FROM costs  

    WHERE promo_id IN  (SELECT promo_id FROM promotions                      

    WHERE promo_cost < ALL                    

    (SELECT MAX(promo_cost) FROM promotions                      

    GROUP BY (promo_end_date-                                 

    promo_begin_date)));

    What would be the outcome of the above SQL statement?

    A. It displays prod IDs in the promo with the lowest cost.

    B. It displays prod IDs in the promos with the lowest cost in the same time interval.

    C. It displays prod IDs in the promos with the highest cost in the same time interval.

    D. It displays prod IDs in the promos with cost less than the highest cost in the same time interval.

    Answer: D

    答案解析:

    1、首先查询出promo_end_date- promo_begin_date期间promo_cost的最大值

    sh@TEST0924> SELECT MAX(promo_cost) FROM promotions
      2  GROUP BY (promo_end_date- promo_begin_date);
     
    MAX(PROMO_COST)
    ---------------
                  0
              98500
                  0
              99900
             100000
              99000
              99300
              95900
              99600
              98000
     
    10 rows selected.
     
    2、<ALL,即小于1查询出来所有的的值,即小于最小值。
    3、按题中查询,即查询出小于MAX(promo_cost) 的所有的值。
    sh@TEST0924>  SELECT prod_id FROM costs
      2  WHERE promo_id IN  (SELECT promo_id FROM promotions
      3  WHERE promo_cost < ALL
      4  (SELECT MAX(promo_cost) FROM promotions
      5  GROUP BY (promo_end_date-
      6  promo_begin_date)));
     
     
    no rows selected
     
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  • 原文地址:https://www.cnblogs.com/hzcya1995/p/13317164.html
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