zoukankan      html  css  js  c++  java
  • OCP-1Z0-051-V9.02-144题

    144. View the Exhibit and examine the structure of the PRODUCTS table.

    You want to display the category with the maximum number of items.

    You issue the following query:

    SQL>SELECT COUNT(*),prod_category_id

    FROM products

    GROUP BY prod_category_id

    HAVING COUNT(*) = (SELECT MAX(COUNT(*)) FROM products); 没有group by

    What is the outcome? 

    A. It executes successfully and gives the correct output.

    B. It executes successfully but does not give the correct output.

    C. It generates an error because the subquery does not have a GROUP BY clause.

    D. It generates an error because = is not valid and should be replaced  by the   IN operator.

    Answer: C

    答案解析:

    1、首先来运行前半句,可见语法是正确的。

     

    sh@TESTDB> SELECT COUNT(*),prod_category_id
      2  FROM products
      3  GROUP BY prod_category_id
      4  HAVING COUNT(*)=2;
      COUNT(*) PROD_CATEGORY_ID
    ---------- ----------------
             2              202

    2、再来运行子查询,报错,缺少group by函数。故选C,子查询缺少group by函数。

     

    sh@TESTDB> SELECT MAX(COUNT(*)) FROM products;
    SELECT MAX(COUNT(*)) FROM products
               *
    ERROR at line 1:
    ORA-00978: nested group function without GROUP BY
  • 相关阅读:
    python实现Linux启动守护进程
    多维监控体系
    python 设计模式
    markdown安装和使用
    cobbler深入学习
    cobbler重装、web、定制化
    cobbler工作流分析
    cobbler安装、部署、测试
    Django中Celery的实现介绍(一)
    centos 搭建git服务器
  • 原文地址:https://www.cnblogs.com/hzcya1995/p/13317218.html
Copyright © 2011-2022 走看看