def fun1(a): return a+3 b=(1,2,3,4,5) print map(lambda x: x + 1,b) C:Python27python.exe C:/Users/TLCB/PycharmProjects/untitled/mycompany/ddd/a15.py [2, 3, 4, 5, 6] lambda 允许你快速地创建只有一行的函数对象