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  • 面试一些简单的编程题目

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    //在有序数组中找出某个数字的位置
    #include<stdio.h>
    int binarySearch(int a[] , int length,int object)
    {
        int head=0,mid=0;
        int tail = length -1;
        while(head<tail)
        {
               mid = (head+tail)/2;
               if ( a[mid] > object)
                   tail = mid -1;
               else if(a[mid]<object)
                   head = mid +1;
               else
                   return mid;
        }
        return -1;
    }
    
    int main()
    {
        int array[] ={ 1,2,3 ,4 ,5, 6,7,8,9,10};
        int result=binarySearch(array,sizeof(array),6);
        printf("%d",result);
        return 0;
    }
    
    
    
    //找出有序数组中出现某数字的次数
    #include<stdio.h>
    int count =0;
    void  binarySearch(int a[] , int head,int tail,int object)
    {
        if(head<=tail)
        {
            int mid = (head+tail)/2;
            if (a[mid] == object)
            {
                count++;
                binarySearch(a,head,mid-1,object);
                binarySearch(a,mid+1,tail,object);
            }
            else if( a[mid] < object)
            {
                binarySearch(a,mid+1,tail,object);
            }
            else
            {
                binarySearch(a,head, mid-1,object);
            }
        }
    }
    
    int main()
    {
        int array[] ={ 1,2,2 ,2 ,2, 2,2,2,9,10};
        binarySearch(array,0,sizeof(array)/4-1,2);
        printf("%d",count);
        return 0;
    }
    
    
    //求数组中最大子数组和
    #include <stdio.h>
    int MaxSum(int a[] ,int length)
    {
        int nStart = 0,nSum=0,i;
        for(i=0; i < length; i++)
        {
            nStart = ( nStart+a[i] ) > a[i]? ( nStart+a[i] ) : a[i];
            nSum = nStart>nSum? nStart:nSum;
        }
        return nSum;
    }
    
    int main()
    {
        int array[]={ 7,-9,8,7,-5,9,10,-20,9,-30,20,49,-50,-60};
        int sum= MaxSum(array,sizeof(array)/4);
        printf("%d",sum);
    }
    
    
    //求最长公共子序列
    
    #include <stdio.h>
    int MaxLength(char a[], char b[],int **c,int **back,int m,int n)
    {
        int i,j;
        for (i=0;i<m;i++)
            for(j=0;j<n;j++)
                back[i][j] = 0;
        for (i=0;i<m;i++) c[i][0] = 0;
        for (j=0;j<n;j++) c[0][j] = 0;
        for (i=1; i<m;i++)
            for (j=1;j<n;j++)
            {
                if ( a[i]==b[j] ) 
                {
                    c[i][j] = c[i-1][j-1] +1;
                    back[i][j] = 1;
                }
                else if( c[i-1][j] >= c[i][j-1] )
                {
                    c[i][j] =c[i-1][j];
                    back[i][j] =2;
                }
                else
                {
                    c[i][j] = c[i][j-1];
                    back[i][j] = 3;
                }
            }
      return c[m -1][n -1];
    }
    
    void LCS(int i,int j, char *a, int **back)
    {
        if(i ==0 || j==0) 
            return;
        if (back[i][j] == 1) 
        {
            LCS(i-1,j-1,a,back);
            printf("%c",a[i]);
        }
        else if(back[i][j] == 2)
        {
            LCS(i-1,j,a,back);
        }
        else
        {
            LCS(i,j-1,a,back);
        }
    }
    
    int main()
    {
        char A[]="ACDWDYEZYXZXXABDYBZZ";
        char B[] ="BYBZACDZYAXXXYZZ";                                                                                                                                                               
        int **C  = new int*[sizeof(A)];
        for (int i=0;i<sizeof(A);i++)
            C[i] = new int[sizeof(B)];
        int **Back = new int*[sizeof(A)];
        for(int i=0;i<sizeof(A);i++)
            Back[i] =new int[sizeof(B)];
        int length = MaxLength(A,B,C,Back,sizeof(A),sizeof(B));
        printf("Max Common Length:  %d\n",length);
        printf("Common String:  ");
        LCS(sizeof(A)-1,sizeof(B)-1,A,Back);
        printf("\nLength Array\n");
        for(int i=0;i<sizeof(A);i++)
        {
            for(int j=0;j<sizeof(B);j++)
                printf("%d  ",C[i][j]);
            printf("\n");
        }
        printf("TraceBack Array\n");
        for(int i=0;i<sizeof(A);i++)
        {
            for(int j=0;j<sizeof(B);j++)
                printf("%d  ",Back[i][j]);
            printf("\n");
        }
    }
    
    
    //约瑟夫环
    
    #include<stdio.h>
    #include <stdlib.h>
    
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    LinkList *create(int n)
    {
        LinkList *p,*q,*head;
        p = (struct Node*)malloc(sizeof(Node));
        p->num=1;
        head =p;
        q = p;
        for(int i=2;i<=n;i++)
        {
            p= (struct Node*)malloc(sizeof(Node));
            p->num =i;
            q->next =p;
            q=p;
        }
        p->next = head;
        return head;
    }
    
    void Jonse(LinkList *&head,int m)
    {
        LinkList *p,*q,*s;
        p=head;
    
        while(p->next != p)
        {
            for(int i=1;i<m;i++)
            {
                q=p;
                p=p->next;
            }
            printf("%d  ",p->num);
            s=p;
            q->next=p->next;
            p = p->next;
            free(s);
        }
        printf("%3d",p->num);
    }
    
    void main()
    {
        LinkList *head;
        int m,n;
        printf("Enter the number of List: ");
        scanf("%d",&m);
        printf("\nEnter the internal of List: ");
        scanf("%d",&n);
        head = create(n);
        Jonse(head,m);
    }
    
    
    
    //链表的倒置
    #include <stdio.h>
    #include <stdlib.h>
    
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    LinkList *create(int n)
    {
        LinkList *p,*q,*head;
        p = (struct Node*)malloc(sizeof(Node));
        p->num=1;
        head =p;
        q = p;
        for(int i=2;i<=n;i++)
        {
            p = (struct Node*)malloc(sizeof(Node));
            p->num = i;
            q->next =p;
            q = p;
        }
        p->next = NULL;
        return head;
    }
    
    void reverse(LinkList  *&head)
    {
        LinkList *p,*q;
        p = head->next;
        q  = p ->next;
        head->next = NULL;
        while( q != NULL)
        {
            p->next = head;
            head =p;
            p =q;
            q = q->next;
        }
        p->next =head;
        head =p;
    }
    
    void List(LinkList *head)
    {
        while(head != NULL)
        {
            printf("%3d",head->num);
            head = head->next;
        }
    }
    
    void main()
    {
        LinkList *head;
        int n;
        printf("Enter the length of the List: ");
        scanf("%d",&n);
        head = create(n);
        printf("Before reverse : ");
        List(head);
        reverse(head);
        printf("\nAfter reverse: ");
        List(head);
    }
    
    //指针,字符串的理解
    
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    void main()
    {
        char *s =(char*)malloc(12);               //这里需要为字符串指针申请内存空间
        const char *sas= "we are the world\0";
        printf("The length of string: %d\n",strlen(sas));
        char *dd[] = { "we","are" ,"the","world","to be better","innocence","somebody","yesterday is history, tomorrow is mystery,but today is gift"};
        char cc[10][10]={"we","are" ,"the","world","be better","innocence","somebody","yesterday"};
        char (*CC)[10] =cc;                 //数组指针出场
        printf("数组指针隆重出场: %s  %s\n", CC,CC[0],CC[1]);
        scanf("%s",s);
        printf("%s",s);
        printf("\n%s",sas);
        for(int i=0;i<sizeof(dd)/4;i++)   //指针数组,可以用sizeof求出数组的长度,指针的字节是4,所以需要除以4
        {
            printf("\n%s",dd[i]);
            if(i==7)
            {
                printf("\n");
                for(int j=0; j<20; j++)   //这里不能使用sizeof(dd[7]),来获取长度,这里只能获取指针的长度
                    printf("%c",dd[i][j]);
            }
        }
    
        for(int i=0; i<sizeof(cc);i++)
        {
            for(int j=0; j<sizeof(cc[10]);j++)
                printf("%c",cc[i][j]);
            printf("\n");
        }
    }
    
    //字符串的快速排序
    
    #include <stdlib.h>
    #include <stdio.h>
    #include <string.h>
    
    int Partition(char **quicksort,int left,int right)
    {
        char *random = quicksort[left];
        int l = left,  r = right+1;
        while (true)
        {
            while( (strcmp(quicksort[++l] , random)<0 ) && l<r) ;
            while( strcmp(quicksort[--r],random) > 0 )  ;
            if( l >= r) 
                break;
            char temp[20]={};
            strcpy(temp,quicksort[l]);
            strcpy(quicksort[l],quicksort[r]);
            strcpy(quicksort[r],quicksort[l]);
        }
        strcpy(quicksort[left],quicksort[r]);
        strcpy(quicksort[r],random);
        return r;
    }
    
    void QuickSort(char **quicksort ,int left,int right)
    {
        if(left < right)
        {
            int part = Partition(quicksort,left,right);
            QuickSort(quicksort,left, part-1);
            QuickSort(quicksort,part+1,right);
        }
    }
    
    void main()
    {
        char *quicksort[ ] = {"me","he","who","she","what","new"};
        QuickSort(quicksort, 0,sizeof(quicksort)/4-1);
        for(int i=0;i<sizeof(quicksort)/4; i++)
            printf("%s  ",quicksort[i]);
    }
    
    
    
    //快速排序
    
    #include <stdio.h>
    #include <stdlib.h>
    int  Partition(int *sort,int left,int right)
    {
        int x=sort[left];
        int l=left, r=right+1;
        while(true)
        {
            while( sort[++l] < x && l < r) ;
            while( sort[--r] > x  ) ;
            if( l >=r)
                break;
            int temp = sort[l];
            sort[l] = sort[r];
            sort[r] = temp;
        }
        sort[left] = sort[r];
        sort[r]   = x;
        return r;
    }
    
    void QuickSort(int *sort,int left,int right)
    {
        if(left<right)
        {
            int part = Partition(sort,left,right);
            QuickSort(sort,left,part-1);
            QuickSort(sort,part+1,right);
        }
    }
    void main()
    {
        int sort[] = {8,3,9,31,32,32,32,33,78,7,10,11,12};
        QuickSort(sort, 0,sizeof(sort)/4-1);
        for(int i=0;i<sizeof(sort)/4; i++)
            printf("%d  ",sort[i]);
    }
    
    
    
    #include <iostream>
    using namespace std;
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    typedef struct LinkQueue
    {
        LinkList *head, *tail;
    }queue;
    
    void insert(queue *Q, int m)
    {
        LinkList *p;
        p = (Node*)malloc(sizeof(Node));
        p->num = m;
        p->next  = NULL;
    
        if(Q->tail == NULL)
        {
            Q->tail = p;
            Q->head =p;
        }
        else
        {
            Q->tail->next =p;
            Q->tail =p;
        }
    }
    
    void del(queue *Q)
    {
        LinkList *p; int x;
    
        if( Q->head == NULL)
        {
            cout<<"The Queue is Empty"<<endl;
        }
        else
        {
            x = Q->head->num;
            cout<<x <<endl;
            p = Q->head;
            if (Q->head == Q->tail)
            {
                Q->head = NULL;
                Q->tail    = NULL;
            }
            else
            {
                Q->head = Q->head->next;
            }
            free(p);
        }
    }
    
    void main()
    {
        queue  *Q =(LinkQueue*)malloc(sizeof(LinkQueue));
        Q->head = NULL;
        Q->tail    = NULL;
        for(int i = 0 ; i <=10; i++)
            insert(Q,i);
        for(int i= 0; i <= 10; i++)
            del(Q);
    }
    
    // 用链表实现的栈
    
    #include <iostream>
    #include <stdio.h>
    #include <array>
    #include <vector>
    #include <list>
    #include <map>
    #include <hash_map>
    #include <queue>
    using namespace std;
    
    typedef struct Node{
        int num;
        struct Node *next;
    }LinkList;
    
    typedef struct Stack{
        LinkList *bottom, *top;
    }stack;
    
    void push(stack *S, int num)
    {
        LinkList *p;
        p = (Node *)malloc(sizeof(Node));
        p->num =num;
        if(S->bottom == NULL)
        {
            S->bottom =p;
            S->top  =p;
            p->next = NULL;
        }
        else
        {
            p->next = S->top;
            S->top  = p;
        }
    }
    
    int pop(stack *S)
    {
        LinkList *p; int x;
        if(S->bottom == NULL)
        {
            cout<< "The Stack is Empty"<<endl;
        }
        else
        {
            x = S->top->num;
            cout<< x<<" ";
            p = S->top;
            if( S->top == S->bottom)
            {
                S->top = NULL;
                S->bottom =NULL;
            }
            else
            {
                S->top = S->top->next;
            }
            free(p);
        }
        return x;
    }
    
    void main()
    {
        stack *S = (Stack *)malloc(sizeof(Stack));
        S->bottom = NULL; S->top = NULL;
        for(int i=0;i<=10;i++)
            push(S,i);
        for(int i=0;i<=10;i++)
            pop(S);
    }
    
    
    //使用栈实现四则运算
    
    #include<iostream>
    #include <stack>
    using namespace std;
    void main()
    {
        stack<int> s_num;
        stack<char> s_oper;
        char *express =new char[100];
        cout<<"Enter the expression:"<<endl;
        cin>>express;
        int sum=0, number1,number2;
        int  len = strlen(express);
        for(int i=0;i < len; i++)
        {
            if(express[i] >= '0' && express[i] <='9')
                sum = sum*10+(express[i] - '0');
            else
            {
                if(express[i] ==' ')
                    continue;
                s_num.push(sum);
                sum=0;
                if(express[i] =='=')
                {
                    while(!s_oper.empty())
                    {
                        number1 = s_num.top();
                        s_num.pop();
                        number2 = s_num.top();
                        s_num.pop();
                        switch(s_oper.top())
                        {
                        case '+':
                            s_num.push(number2+number1);
                            break;
                        case '-':
                            s_num.push(number2-number1);
                            break;
                        case '*':
                            s_num.push(number2*number1);
                            break;
                        case '/':
                            s_num.push(number2/number1);
                            break;
                        default:
                            break;
                        }
                    s_oper.pop();
                    }
                }
    
                if(!s_oper.empty())
                {
                    if(s_oper.top() =='*' ||  s_oper.top() == '/')
                    {
                        number1 = s_num.top();
                        s_num.pop();
                        number2 = s_num.top();
                        s_num.pop();
                        if(s_oper.top() =='*')
                            s_num.push(number2*number1);
                        else
                            s_num.push(number2/number1);
                        s_oper.pop();
                    }
                }
    
                switch(express[i])
                {
                    case '+':
                        if(s_oper.empty())
                            s_oper.push('+');
                        else
                        {
                            number1 = s_num.top();
                            s_num.pop();
                            number2 = s_num.top();
                            s_num.pop();
                            if(s_oper.top() == '+')
                                s_num.push(number2+number1);
                            else
                                s_num.push(number2-number1);
                            s_oper.pop();
                            s_oper.push('+');
                        }
                        break;
                    case '-':
                        if(s_oper.empty())
                            s_oper.push('-');
                        else
                        {
                            number1 = s_num.top();
                            s_num.pop();
                            number2 = s_num.top();
                            s_num.pop();
                            if(s_oper.top() == '+')
                                s_num.push(number2+number1);
                            else
                                s_num.push(number2-number1);
                            s_oper.pop();
                            s_oper.push('-');
                        }
                        break;
                    case '*':
                        s_oper.push('*');
                        break;
                    case '/':
                        s_oper.push('/');
                        break;
                    default:
                        break;
                }
            }
        }
        cout<<"Sum is : "<< s_num.top()<<endl;
    }
    
    
    
    //两个栈实现队列的功能
    #include <iostream>
    #include <stack>
    using namespace std;
    template <class T>
    struct Queue
    {
        void push(T &t)
        {
            s1.push(t);
        }
    
        T front()
        {
            if(s2.empty())
            {
                if(s1.size() == 0) throw;
                while(!s1.empty())
                {
                    s2.push(s1.top());
                    s1.pop();
                }
            }
            return s2.top();
        }
    
    
        void pop()
        {
            if(s2.empty())
            {
                while(!s1.empty())
                {
                    s2.push(s1.top());
                    s1.pop();
                }
            }
            if(!s2.empty())
                s2.pop();
        }
    
        stack<T> s1;
        stack<T> s2;
    };
    
    int main()
    {
        Queue<int> Q;
        int i;
        for ( i=0; i<10; ++i)
            Q.push(i);
        for(i=0;i<10;++i)
        {
            cout<< Q.front()<<endl;
            Q.pop();
        }
        return 0;
    }
    
    //整数转换为字符串 itoa函数
    #include <iostream>
    using namespace std;
    void main()
    {
        int m,i=0;
        char temp[10], str[10];
        cin>> m;
        while(m != 0)
        {
            temp[i++] = m%10+'0';
            m = m/10;
        }
        temp[i] ='\0';
        str[i] ='\0';
        int j=0;
        while(temp[j] != '\0')
        {
            str[--i] = temp[j++];
        }
        for(i=0;i<=j;i++)
            cout<<str[i];
    }
    
    //字符串转换为整数 atoi函数
    #include <iostream>
    using namespace std;
    void main()
    {
        char *str=new char[10];
        cin>>str;
        int num=0;
        int len = strlen(str);
        for(int i=0;i<len;i++)
            num = num*10 + (str[i] -'0');
        cout<<num;
    }
    
    //字符串复制
    
    #include <iostream>
    #include <stdio.h>
    #include <assert.h>
    using namespace std;
    
    char * strcpy(char *dest, const char *source)
    {
        assert((dest != NULL )&&(source != NULL));
        char *address = dest;
        while( *source != '\0')
            *dest++ = *source++;
        *dest ='\0';
        return address;
    }
    
    void main()
    {
        char *source = "We are the World";
        char *dest = new char[20];
        char *address=strcpy(dest,source);
        cout<<address<<endl;
    }
    
    
    //循环右移字符串n位
    #include <iostream>
    using namespace std;
    void LoopMove(char *str,int steps)
    {
        int  n= strlen(str) - steps;
        char temp[100]; 
        strcpy(temp, str+n);
        strcpy(temp+steps,str);
        *(temp+strlen(str))  = '\0';
        strcpy(str,temp);
    }
    
    
    void LoopMove(char *str,int steps)
    {
        int n = strlen(str) - steps;
        char temp[100];
        memcpy(temp,str+n,steps);
        memcpy(temp+steps,str,n);
        memcpy(str,temp,n+steps);
    }
    
    void main()
    {
        char str[30];                         //char *str = "I live in Guangzhou",str[i] ='m'; 默认指针指向常量,不可修改
        int i;
        for(i=0;i<9;i++)
            str[i] =i+'0';
        str[i]='\0';
        LoopMove(str,4);
        cout<<str<<endl;
    }
    
    //map结构记录字母或单词出现的次数, 还没实现根据value来排序。
    
    #include <iostream>
    #include <map>
    #include <string.h>
    using namespace std;
    
    void main()
    {
        map<char,int> m ;
        map<char,int>::iterator m_iter;
        char *str = "Yesterday is history,tomorrow is mystery,but today is gift";
        while(*str != '\0')
        {
            if(m[*str] >= 1)
                m[*str]++;
            else
                m[*str] = 1;
            str++;
        }
        for(m_iter = m.begin(); m_iter !=m.end(); m_iter++)
            cout<<m_iter->first <<" :" <<m_iter->second <<" ";
    
    
        map<string,int> word_map;
        map<string,int>::iterator word_iter;
        string bb[10]={"Yesterday","is","history","tomorrow","is","mystery","but","today", "is","gift"};
        for (int i=0;i<10;i++)
        {
            if(word_map[bb[i] ] >=1)
                word_map[ bb[i] ] ++;
            else
                word_map[bb[i]] = 1;
        }
        for(word_iter = word_map.begin(); word_iter !=word_map.end(); word_iter++)
            cout << word_iter->first.c_str() <<" :" <<word_iter->second <<" ";
    }
    
    
    //qsort函数字符串的快速排序
    
    #include <iostream>
    using namespace std;
    
    int comp( const void *A, const void *B)
    {
        return strcmp((char*)A, (char*)B);
    }
    
    int comp_num(const void *A, const void *B)
    {
        if(*((int*)A) >= *((int*)B) ) return 1;
        else return -1;
    }
    
    void main()
    {
        const int row= 5;
        const int col = 10;
        char a[row][col] = { "hzhida", "is", "a ","diligent","man"};
        qsort(a,row,sizeof(a[0]),comp);
        for(int i=0;i<row;i++)
            cout<<a[i] <<"\t";
    
        int A[col] ={100,55,20,30,50,60,70,90,67,10};
        qsort(A,sizeof(A)/sizeof(int),sizeof(int),comp_num);
        for(int i=0;i<col;i++)
            cout<<A[i] <<"\t";
    }
    
    
    //String 类
    
    #include <iostream> 
    using namespace std;
    class String
    {
    public:
        String(const char* str = NULL);              //普通构造函数
        String(const String &other);                   //拷贝构造函数
        ~String(void);                                         //析构函数
        String & operator =(const String &other); // 赋值函数
        void  print();
    private:
        char *m_data;
    };
    
    String::String(const char *str )
    {
        if (str == NULL)
        {
            m_data = new char[1];
            *m_data = '\0';
        }
        else
        {
            m_data = new char[strlen(str)+1];
            strcpy(m_data, str);
        }
    }
    
    String::~String(void)
    {
        delete m_data;
    }
    
    String::String(const String &other)
    {
        m_data = new char[strlen(other.m_data)+1];
        strcpy(m_data, other.m_data);
    }
    
    String &String::operator=(const String &other)
    {
        if(this == &other)
            return *this;
        delete [] m_data;
        m_data = new char[strlen(other.m_data) +1];
        strcpy(m_data,other.m_data);
        return *this;
    }
    
    void String::print()
    {
        cout<<m_data<<endl;
    }
    
    void main()
    {
        const char *m="long ago, in ancient China, the peakcock rule over the goldmen city";
        String M(m);                 //普通构造函数
        M.print();
        String Z(M);                    //拷贝构造函数
        Z.print();
        String Y = M;                //赋值函数
        Y.print();
    }
    
    
    汉诺塔问题
    #include <iostream>
    using namespace std;
    void TowerHanoi(int n,char x, char y, char z)
    {
        if(n)
        {
            TowerHanoi(n-1, x, z, y);
            cout<< "Move top disk from: "<< char(x) <<"   to: "<<char(y)<<endl;
            TowerHanoi(n-1, z, y, x);
        }
    }
    
    void main()
    {
        int n=0;
        cout <<"input the level of tower: ";
        cin>>n;
        TowerHanoi(n, 'A','B','C');
    }
    
    
    #include <iostream>
    using namespace std;
    void TransferString(const char *pInputStr, long lInputLen,char *pOutputStr)
    {
        int i;
        for(i=0; i<lInputLen;i++)
        {
            if( pInputStr[i] > 'A' &&  pInputStr[i] < 'V')
            {
                pOutputStr[i] = pInputStr[i] + (char)37;
            }
            else if(pInputStr[i] >= 'V' && pInputStr[i] <= 'Z')
            {
                pOutputStr[i]  = pInputStr[i] + (char)11;
            }
            else 
                pOutputStr[i]  = pInputStr[i];
        }
        pOutputStr[i] ='\0';
    }
    
    void main()
    {
        char *aa="Axs3mWss";
        char  *bb = new char[20];
        TransferString(aa,strlen(aa),bb);
        cout<<bb<<endl;
    }
    
    
    #include <iostream>
    using namespace std;
    void main()
    {
        char *aa = new char[100];
        char *bb = new char[100];
        cin>>aa;
        int i;
        for( i=0; i<strlen(aa); i++)
            bb[strlen(aa) - i -1] = aa[i];
        for(i=0; i<strlen(aa); i++)
        {
            if(aa[i] == bb[i])
                continue;
            else
            {
                cout<<"NO"<<endl;
                break;
            }
        }
        if( i == strlen(aa) )
            cout<< "YES"<<endl;
    }
    
    #include <iostream>
    using namespace std;
    void main()
    {
        char *aa = new char[100];
        cin>>aa;
        int i;
        for(i=0; i<strlen(aa)/2;i++)
           {
               if(aa[i] == (aa[strlen(aa) -i-1]))
                   continue;
               else
               {
                   cout<<"NO"<<endl;
                   break;
               }
        }
        if( i == strlen(aa)/2)
            cout<<"YES"<<endl;
    }
    Live together,or Die alone!
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  • 原文地址:https://www.cnblogs.com/hzhida/p/2709213.html
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