zoukankan      html  css  js  c++  java
  • 面试一些简单的编程题目

    View Code
    //在有序数组中找出某个数字的位置
    #include<stdio.h>
    int binarySearch(int a[] , int length,int object)
    {
        int head=0,mid=0;
        int tail = length -1;
        while(head<tail)
        {
               mid = (head+tail)/2;
               if ( a[mid] > object)
                   tail = mid -1;
               else if(a[mid]<object)
                   head = mid +1;
               else
                   return mid;
        }
        return -1;
    }
    
    int main()
    {
        int array[] ={ 1,2,3 ,4 ,5, 6,7,8,9,10};
        int result=binarySearch(array,sizeof(array),6);
        printf("%d",result);
        return 0;
    }
    
    
    
    //找出有序数组中出现某数字的次数
    #include<stdio.h>
    int count =0;
    void  binarySearch(int a[] , int head,int tail,int object)
    {
        if(head<=tail)
        {
            int mid = (head+tail)/2;
            if (a[mid] == object)
            {
                count++;
                binarySearch(a,head,mid-1,object);
                binarySearch(a,mid+1,tail,object);
            }
            else if( a[mid] < object)
            {
                binarySearch(a,mid+1,tail,object);
            }
            else
            {
                binarySearch(a,head, mid-1,object);
            }
        }
    }
    
    int main()
    {
        int array[] ={ 1,2,2 ,2 ,2, 2,2,2,9,10};
        binarySearch(array,0,sizeof(array)/4-1,2);
        printf("%d",count);
        return 0;
    }
    
    
    //求数组中最大子数组和
    #include <stdio.h>
    int MaxSum(int a[] ,int length)
    {
        int nStart = 0,nSum=0,i;
        for(i=0; i < length; i++)
        {
            nStart = ( nStart+a[i] ) > a[i]? ( nStart+a[i] ) : a[i];
            nSum = nStart>nSum? nStart:nSum;
        }
        return nSum;
    }
    
    int main()
    {
        int array[]={ 7,-9,8,7,-5,9,10,-20,9,-30,20,49,-50,-60};
        int sum= MaxSum(array,sizeof(array)/4);
        printf("%d",sum);
    }
    
    
    //求最长公共子序列
    
    #include <stdio.h>
    int MaxLength(char a[], char b[],int **c,int **back,int m,int n)
    {
        int i,j;
        for (i=0;i<m;i++)
            for(j=0;j<n;j++)
                back[i][j] = 0;
        for (i=0;i<m;i++) c[i][0] = 0;
        for (j=0;j<n;j++) c[0][j] = 0;
        for (i=1; i<m;i++)
            for (j=1;j<n;j++)
            {
                if ( a[i]==b[j] ) 
                {
                    c[i][j] = c[i-1][j-1] +1;
                    back[i][j] = 1;
                }
                else if( c[i-1][j] >= c[i][j-1] )
                {
                    c[i][j] =c[i-1][j];
                    back[i][j] =2;
                }
                else
                {
                    c[i][j] = c[i][j-1];
                    back[i][j] = 3;
                }
            }
      return c[m -1][n -1];
    }
    
    void LCS(int i,int j, char *a, int **back)
    {
        if(i ==0 || j==0) 
            return;
        if (back[i][j] == 1) 
        {
            LCS(i-1,j-1,a,back);
            printf("%c",a[i]);
        }
        else if(back[i][j] == 2)
        {
            LCS(i-1,j,a,back);
        }
        else
        {
            LCS(i,j-1,a,back);
        }
    }
    
    int main()
    {
        char A[]="ACDWDYEZYXZXXABDYBZZ";
        char B[] ="BYBZACDZYAXXXYZZ";                                                                                                                                                               
        int **C  = new int*[sizeof(A)];
        for (int i=0;i<sizeof(A);i++)
            C[i] = new int[sizeof(B)];
        int **Back = new int*[sizeof(A)];
        for(int i=0;i<sizeof(A);i++)
            Back[i] =new int[sizeof(B)];
        int length = MaxLength(A,B,C,Back,sizeof(A),sizeof(B));
        printf("Max Common Length:  %d\n",length);
        printf("Common String:  ");
        LCS(sizeof(A)-1,sizeof(B)-1,A,Back);
        printf("\nLength Array\n");
        for(int i=0;i<sizeof(A);i++)
        {
            for(int j=0;j<sizeof(B);j++)
                printf("%d  ",C[i][j]);
            printf("\n");
        }
        printf("TraceBack Array\n");
        for(int i=0;i<sizeof(A);i++)
        {
            for(int j=0;j<sizeof(B);j++)
                printf("%d  ",Back[i][j]);
            printf("\n");
        }
    }
    
    
    //约瑟夫环
    
    #include<stdio.h>
    #include <stdlib.h>
    
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    LinkList *create(int n)
    {
        LinkList *p,*q,*head;
        p = (struct Node*)malloc(sizeof(Node));
        p->num=1;
        head =p;
        q = p;
        for(int i=2;i<=n;i++)
        {
            p= (struct Node*)malloc(sizeof(Node));
            p->num =i;
            q->next =p;
            q=p;
        }
        p->next = head;
        return head;
    }
    
    void Jonse(LinkList *&head,int m)
    {
        LinkList *p,*q,*s;
        p=head;
    
        while(p->next != p)
        {
            for(int i=1;i<m;i++)
            {
                q=p;
                p=p->next;
            }
            printf("%d  ",p->num);
            s=p;
            q->next=p->next;
            p = p->next;
            free(s);
        }
        printf("%3d",p->num);
    }
    
    void main()
    {
        LinkList *head;
        int m,n;
        printf("Enter the number of List: ");
        scanf("%d",&m);
        printf("\nEnter the internal of List: ");
        scanf("%d",&n);
        head = create(n);
        Jonse(head,m);
    }
    
    
    
    //链表的倒置
    #include <stdio.h>
    #include <stdlib.h>
    
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    LinkList *create(int n)
    {
        LinkList *p,*q,*head;
        p = (struct Node*)malloc(sizeof(Node));
        p->num=1;
        head =p;
        q = p;
        for(int i=2;i<=n;i++)
        {
            p = (struct Node*)malloc(sizeof(Node));
            p->num = i;
            q->next =p;
            q = p;
        }
        p->next = NULL;
        return head;
    }
    
    void reverse(LinkList  *&head)
    {
        LinkList *p,*q;
        p = head->next;
        q  = p ->next;
        head->next = NULL;
        while( q != NULL)
        {
            p->next = head;
            head =p;
            p =q;
            q = q->next;
        }
        p->next =head;
        head =p;
    }
    
    void List(LinkList *head)
    {
        while(head != NULL)
        {
            printf("%3d",head->num);
            head = head->next;
        }
    }
    
    void main()
    {
        LinkList *head;
        int n;
        printf("Enter the length of the List: ");
        scanf("%d",&n);
        head = create(n);
        printf("Before reverse : ");
        List(head);
        reverse(head);
        printf("\nAfter reverse: ");
        List(head);
    }
    
    //指针,字符串的理解
    
    #include <stdio.h>
    #include <stdlib.h>
    #include <string.h>
    void main()
    {
        char *s =(char*)malloc(12);               //这里需要为字符串指针申请内存空间
        const char *sas= "we are the world\0";
        printf("The length of string: %d\n",strlen(sas));
        char *dd[] = { "we","are" ,"the","world","to be better","innocence","somebody","yesterday is history, tomorrow is mystery,but today is gift"};
        char cc[10][10]={"we","are" ,"the","world","be better","innocence","somebody","yesterday"};
        char (*CC)[10] =cc;                 //数组指针出场
        printf("数组指针隆重出场: %s  %s\n", CC,CC[0],CC[1]);
        scanf("%s",s);
        printf("%s",s);
        printf("\n%s",sas);
        for(int i=0;i<sizeof(dd)/4;i++)   //指针数组,可以用sizeof求出数组的长度,指针的字节是4,所以需要除以4
        {
            printf("\n%s",dd[i]);
            if(i==7)
            {
                printf("\n");
                for(int j=0; j<20; j++)   //这里不能使用sizeof(dd[7]),来获取长度,这里只能获取指针的长度
                    printf("%c",dd[i][j]);
            }
        }
    
        for(int i=0; i<sizeof(cc);i++)
        {
            for(int j=0; j<sizeof(cc[10]);j++)
                printf("%c",cc[i][j]);
            printf("\n");
        }
    }
    
    //字符串的快速排序
    
    #include <stdlib.h>
    #include <stdio.h>
    #include <string.h>
    
    int Partition(char **quicksort,int left,int right)
    {
        char *random = quicksort[left];
        int l = left,  r = right+1;
        while (true)
        {
            while( (strcmp(quicksort[++l] , random)<0 ) && l<r) ;
            while( strcmp(quicksort[--r],random) > 0 )  ;
            if( l >= r) 
                break;
            char temp[20]={};
            strcpy(temp,quicksort[l]);
            strcpy(quicksort[l],quicksort[r]);
            strcpy(quicksort[r],quicksort[l]);
        }
        strcpy(quicksort[left],quicksort[r]);
        strcpy(quicksort[r],random);
        return r;
    }
    
    void QuickSort(char **quicksort ,int left,int right)
    {
        if(left < right)
        {
            int part = Partition(quicksort,left,right);
            QuickSort(quicksort,left, part-1);
            QuickSort(quicksort,part+1,right);
        }
    }
    
    void main()
    {
        char *quicksort[ ] = {"me","he","who","she","what","new"};
        QuickSort(quicksort, 0,sizeof(quicksort)/4-1);
        for(int i=0;i<sizeof(quicksort)/4; i++)
            printf("%s  ",quicksort[i]);
    }
    
    
    
    //快速排序
    
    #include <stdio.h>
    #include <stdlib.h>
    int  Partition(int *sort,int left,int right)
    {
        int x=sort[left];
        int l=left, r=right+1;
        while(true)
        {
            while( sort[++l] < x && l < r) ;
            while( sort[--r] > x  ) ;
            if( l >=r)
                break;
            int temp = sort[l];
            sort[l] = sort[r];
            sort[r] = temp;
        }
        sort[left] = sort[r];
        sort[r]   = x;
        return r;
    }
    
    void QuickSort(int *sort,int left,int right)
    {
        if(left<right)
        {
            int part = Partition(sort,left,right);
            QuickSort(sort,left,part-1);
            QuickSort(sort,part+1,right);
        }
    }
    void main()
    {
        int sort[] = {8,3,9,31,32,32,32,33,78,7,10,11,12};
        QuickSort(sort, 0,sizeof(sort)/4-1);
        for(int i=0;i<sizeof(sort)/4; i++)
            printf("%d  ",sort[i]);
    }
    
    
    
    #include <iostream>
    using namespace std;
    typedef struct Node
    {
        int num;
        struct Node *next;
    }LinkList;
    
    typedef struct LinkQueue
    {
        LinkList *head, *tail;
    }queue;
    
    void insert(queue *Q, int m)
    {
        LinkList *p;
        p = (Node*)malloc(sizeof(Node));
        p->num = m;
        p->next  = NULL;
    
        if(Q->tail == NULL)
        {
            Q->tail = p;
            Q->head =p;
        }
        else
        {
            Q->tail->next =p;
            Q->tail =p;
        }
    }
    
    void del(queue *Q)
    {
        LinkList *p; int x;
    
        if( Q->head == NULL)
        {
            cout<<"The Queue is Empty"<<endl;
        }
        else
        {
            x = Q->head->num;
            cout<<x <<endl;
            p = Q->head;
            if (Q->head == Q->tail)
            {
                Q->head = NULL;
                Q->tail    = NULL;
            }
            else
            {
                Q->head = Q->head->next;
            }
            free(p);
        }
    }
    
    void main()
    {
        queue  *Q =(LinkQueue*)malloc(sizeof(LinkQueue));
        Q->head = NULL;
        Q->tail    = NULL;
        for(int i = 0 ; i <=10; i++)
            insert(Q,i);
        for(int i= 0; i <= 10; i++)
            del(Q);
    }
    
    // 用链表实现的栈
    
    #include <iostream>
    #include <stdio.h>
    #include <array>
    #include <vector>
    #include <list>
    #include <map>
    #include <hash_map>
    #include <queue>
    using namespace std;
    
    typedef struct Node{
        int num;
        struct Node *next;
    }LinkList;
    
    typedef struct Stack{
        LinkList *bottom, *top;
    }stack;
    
    void push(stack *S, int num)
    {
        LinkList *p;
        p = (Node *)malloc(sizeof(Node));
        p->num =num;
        if(S->bottom == NULL)
        {
            S->bottom =p;
            S->top  =p;
            p->next = NULL;
        }
        else
        {
            p->next = S->top;
            S->top  = p;
        }
    }
    
    int pop(stack *S)
    {
        LinkList *p; int x;
        if(S->bottom == NULL)
        {
            cout<< "The Stack is Empty"<<endl;
        }
        else
        {
            x = S->top->num;
            cout<< x<<" ";
            p = S->top;
            if( S->top == S->bottom)
            {
                S->top = NULL;
                S->bottom =NULL;
            }
            else
            {
                S->top = S->top->next;
            }
            free(p);
        }
        return x;
    }
    
    void main()
    {
        stack *S = (Stack *)malloc(sizeof(Stack));
        S->bottom = NULL; S->top = NULL;
        for(int i=0;i<=10;i++)
            push(S,i);
        for(int i=0;i<=10;i++)
            pop(S);
    }
    
    
    //使用栈实现四则运算
    
    #include<iostream>
    #include <stack>
    using namespace std;
    void main()
    {
        stack<int> s_num;
        stack<char> s_oper;
        char *express =new char[100];
        cout<<"Enter the expression:"<<endl;
        cin>>express;
        int sum=0, number1,number2;
        int  len = strlen(express);
        for(int i=0;i < len; i++)
        {
            if(express[i] >= '0' && express[i] <='9')
                sum = sum*10+(express[i] - '0');
            else
            {
                if(express[i] ==' ')
                    continue;
                s_num.push(sum);
                sum=0;
                if(express[i] =='=')
                {
                    while(!s_oper.empty())
                    {
                        number1 = s_num.top();
                        s_num.pop();
                        number2 = s_num.top();
                        s_num.pop();
                        switch(s_oper.top())
                        {
                        case '+':
                            s_num.push(number2+number1);
                            break;
                        case '-':
                            s_num.push(number2-number1);
                            break;
                        case '*':
                            s_num.push(number2*number1);
                            break;
                        case '/':
                            s_num.push(number2/number1);
                            break;
                        default:
                            break;
                        }
                    s_oper.pop();
                    }
                }
    
                if(!s_oper.empty())
                {
                    if(s_oper.top() =='*' ||  s_oper.top() == '/')
                    {
                        number1 = s_num.top();
                        s_num.pop();
                        number2 = s_num.top();
                        s_num.pop();
                        if(s_oper.top() =='*')
                            s_num.push(number2*number1);
                        else
                            s_num.push(number2/number1);
                        s_oper.pop();
                    }
                }
    
                switch(express[i])
                {
                    case '+':
                        if(s_oper.empty())
                            s_oper.push('+');
                        else
                        {
                            number1 = s_num.top();
                            s_num.pop();
                            number2 = s_num.top();
                            s_num.pop();
                            if(s_oper.top() == '+')
                                s_num.push(number2+number1);
                            else
                                s_num.push(number2-number1);
                            s_oper.pop();
                            s_oper.push('+');
                        }
                        break;
                    case '-':
                        if(s_oper.empty())
                            s_oper.push('-');
                        else
                        {
                            number1 = s_num.top();
                            s_num.pop();
                            number2 = s_num.top();
                            s_num.pop();
                            if(s_oper.top() == '+')
                                s_num.push(number2+number1);
                            else
                                s_num.push(number2-number1);
                            s_oper.pop();
                            s_oper.push('-');
                        }
                        break;
                    case '*':
                        s_oper.push('*');
                        break;
                    case '/':
                        s_oper.push('/');
                        break;
                    default:
                        break;
                }
            }
        }
        cout<<"Sum is : "<< s_num.top()<<endl;
    }
    
    
    
    //两个栈实现队列的功能
    #include <iostream>
    #include <stack>
    using namespace std;
    template <class T>
    struct Queue
    {
        void push(T &t)
        {
            s1.push(t);
        }
    
        T front()
        {
            if(s2.empty())
            {
                if(s1.size() == 0) throw;
                while(!s1.empty())
                {
                    s2.push(s1.top());
                    s1.pop();
                }
            }
            return s2.top();
        }
    
    
        void pop()
        {
            if(s2.empty())
            {
                while(!s1.empty())
                {
                    s2.push(s1.top());
                    s1.pop();
                }
            }
            if(!s2.empty())
                s2.pop();
        }
    
        stack<T> s1;
        stack<T> s2;
    };
    
    int main()
    {
        Queue<int> Q;
        int i;
        for ( i=0; i<10; ++i)
            Q.push(i);
        for(i=0;i<10;++i)
        {
            cout<< Q.front()<<endl;
            Q.pop();
        }
        return 0;
    }
    
    //整数转换为字符串 itoa函数
    #include <iostream>
    using namespace std;
    void main()
    {
        int m,i=0;
        char temp[10], str[10];
        cin>> m;
        while(m != 0)
        {
            temp[i++] = m%10+'0';
            m = m/10;
        }
        temp[i] ='\0';
        str[i] ='\0';
        int j=0;
        while(temp[j] != '\0')
        {
            str[--i] = temp[j++];
        }
        for(i=0;i<=j;i++)
            cout<<str[i];
    }
    
    //字符串转换为整数 atoi函数
    #include <iostream>
    using namespace std;
    void main()
    {
        char *str=new char[10];
        cin>>str;
        int num=0;
        int len = strlen(str);
        for(int i=0;i<len;i++)
            num = num*10 + (str[i] -'0');
        cout<<num;
    }
    
    //字符串复制
    
    #include <iostream>
    #include <stdio.h>
    #include <assert.h>
    using namespace std;
    
    char * strcpy(char *dest, const char *source)
    {
        assert((dest != NULL )&&(source != NULL));
        char *address = dest;
        while( *source != '\0')
            *dest++ = *source++;
        *dest ='\0';
        return address;
    }
    
    void main()
    {
        char *source = "We are the World";
        char *dest = new char[20];
        char *address=strcpy(dest,source);
        cout<<address<<endl;
    }
    
    
    //循环右移字符串n位
    #include <iostream>
    using namespace std;
    void LoopMove(char *str,int steps)
    {
        int  n= strlen(str) - steps;
        char temp[100]; 
        strcpy(temp, str+n);
        strcpy(temp+steps,str);
        *(temp+strlen(str))  = '\0';
        strcpy(str,temp);
    }
    
    
    void LoopMove(char *str,int steps)
    {
        int n = strlen(str) - steps;
        char temp[100];
        memcpy(temp,str+n,steps);
        memcpy(temp+steps,str,n);
        memcpy(str,temp,n+steps);
    }
    
    void main()
    {
        char str[30];                         //char *str = "I live in Guangzhou",str[i] ='m'; 默认指针指向常量,不可修改
        int i;
        for(i=0;i<9;i++)
            str[i] =i+'0';
        str[i]='\0';
        LoopMove(str,4);
        cout<<str<<endl;
    }
    
    //map结构记录字母或单词出现的次数, 还没实现根据value来排序。
    
    #include <iostream>
    #include <map>
    #include <string.h>
    using namespace std;
    
    void main()
    {
        map<char,int> m ;
        map<char,int>::iterator m_iter;
        char *str = "Yesterday is history,tomorrow is mystery,but today is gift";
        while(*str != '\0')
        {
            if(m[*str] >= 1)
                m[*str]++;
            else
                m[*str] = 1;
            str++;
        }
        for(m_iter = m.begin(); m_iter !=m.end(); m_iter++)
            cout<<m_iter->first <<" :" <<m_iter->second <<" ";
    
    
        map<string,int> word_map;
        map<string,int>::iterator word_iter;
        string bb[10]={"Yesterday","is","history","tomorrow","is","mystery","but","today", "is","gift"};
        for (int i=0;i<10;i++)
        {
            if(word_map[bb[i] ] >=1)
                word_map[ bb[i] ] ++;
            else
                word_map[bb[i]] = 1;
        }
        for(word_iter = word_map.begin(); word_iter !=word_map.end(); word_iter++)
            cout << word_iter->first.c_str() <<" :" <<word_iter->second <<" ";
    }
    
    
    //qsort函数字符串的快速排序
    
    #include <iostream>
    using namespace std;
    
    int comp( const void *A, const void *B)
    {
        return strcmp((char*)A, (char*)B);
    }
    
    int comp_num(const void *A, const void *B)
    {
        if(*((int*)A) >= *((int*)B) ) return 1;
        else return -1;
    }
    
    void main()
    {
        const int row= 5;
        const int col = 10;
        char a[row][col] = { "hzhida", "is", "a ","diligent","man"};
        qsort(a,row,sizeof(a[0]),comp);
        for(int i=0;i<row;i++)
            cout<<a[i] <<"\t";
    
        int A[col] ={100,55,20,30,50,60,70,90,67,10};
        qsort(A,sizeof(A)/sizeof(int),sizeof(int),comp_num);
        for(int i=0;i<col;i++)
            cout<<A[i] <<"\t";
    }
    
    
    //String 类
    
    #include <iostream> 
    using namespace std;
    class String
    {
    public:
        String(const char* str = NULL);              //普通构造函数
        String(const String &other);                   //拷贝构造函数
        ~String(void);                                         //析构函数
        String & operator =(const String &other); // 赋值函数
        void  print();
    private:
        char *m_data;
    };
    
    String::String(const char *str )
    {
        if (str == NULL)
        {
            m_data = new char[1];
            *m_data = '\0';
        }
        else
        {
            m_data = new char[strlen(str)+1];
            strcpy(m_data, str);
        }
    }
    
    String::~String(void)
    {
        delete m_data;
    }
    
    String::String(const String &other)
    {
        m_data = new char[strlen(other.m_data)+1];
        strcpy(m_data, other.m_data);
    }
    
    String &String::operator=(const String &other)
    {
        if(this == &other)
            return *this;
        delete [] m_data;
        m_data = new char[strlen(other.m_data) +1];
        strcpy(m_data,other.m_data);
        return *this;
    }
    
    void String::print()
    {
        cout<<m_data<<endl;
    }
    
    void main()
    {
        const char *m="long ago, in ancient China, the peakcock rule over the goldmen city";
        String M(m);                 //普通构造函数
        M.print();
        String Z(M);                    //拷贝构造函数
        Z.print();
        String Y = M;                //赋值函数
        Y.print();
    }
    
    
    汉诺塔问题
    #include <iostream>
    using namespace std;
    void TowerHanoi(int n,char x, char y, char z)
    {
        if(n)
        {
            TowerHanoi(n-1, x, z, y);
            cout<< "Move top disk from: "<< char(x) <<"   to: "<<char(y)<<endl;
            TowerHanoi(n-1, z, y, x);
        }
    }
    
    void main()
    {
        int n=0;
        cout <<"input the level of tower: ";
        cin>>n;
        TowerHanoi(n, 'A','B','C');
    }
    
    
    #include <iostream>
    using namespace std;
    void TransferString(const char *pInputStr, long lInputLen,char *pOutputStr)
    {
        int i;
        for(i=0; i<lInputLen;i++)
        {
            if( pInputStr[i] > 'A' &&  pInputStr[i] < 'V')
            {
                pOutputStr[i] = pInputStr[i] + (char)37;
            }
            else if(pInputStr[i] >= 'V' && pInputStr[i] <= 'Z')
            {
                pOutputStr[i]  = pInputStr[i] + (char)11;
            }
            else 
                pOutputStr[i]  = pInputStr[i];
        }
        pOutputStr[i] ='\0';
    }
    
    void main()
    {
        char *aa="Axs3mWss";
        char  *bb = new char[20];
        TransferString(aa,strlen(aa),bb);
        cout<<bb<<endl;
    }
    
    
    #include <iostream>
    using namespace std;
    void main()
    {
        char *aa = new char[100];
        char *bb = new char[100];
        cin>>aa;
        int i;
        for( i=0; i<strlen(aa); i++)
            bb[strlen(aa) - i -1] = aa[i];
        for(i=0; i<strlen(aa); i++)
        {
            if(aa[i] == bb[i])
                continue;
            else
            {
                cout<<"NO"<<endl;
                break;
            }
        }
        if( i == strlen(aa) )
            cout<< "YES"<<endl;
    }
    
    #include <iostream>
    using namespace std;
    void main()
    {
        char *aa = new char[100];
        cin>>aa;
        int i;
        for(i=0; i<strlen(aa)/2;i++)
           {
               if(aa[i] == (aa[strlen(aa) -i-1]))
                   continue;
               else
               {
                   cout<<"NO"<<endl;
                   break;
               }
        }
        if( i == strlen(aa)/2)
            cout<<"YES"<<endl;
    }
    Live together,or Die alone!
  • 相关阅读:
    Construct Binary Tree from Preorder and Inorder Traversal
    Construct Binary Tree from Inorder and Postorder Traversal
    Maximum Depth of Binary Tree
    Sharepoint 2013 创建TimeJob 自动发送邮件
    IE8 不能够在Sharepoint平台上在线打开Office文档解决方案
    TFS安装与管理
    局域网通过IP查看对方计算机名,通过计算机名查看对方IP以及查看在线所有电脑IP
    JS 隐藏Sharepoint中List Item View页面的某一个字段
    SharePoint Calculated Column Formulas & Functions
    JS 两个一组数组转二维数组
  • 原文地址:https://www.cnblogs.com/hzhida/p/2709213.html
Copyright © 2011-2022 走看看