实现搜索功能

1. 准备视图函数search()

• #查询
  @app.route('/search/')
  def search():

1. 修改base.html 中搜索输入框所在的
   1. <form action="{{ url_for('search') }}" method="get">
   2.    <input name="q" type="text" placeholder="请输入关键字">
      

      <form action="{{ url_for('search') }}" method="get" class="navbar-form navbar-left">
              <input type="text" name="title" class="form-control" placeholder="请输入搜索内容">
              <button class="btn btn-default" type="submit"><span class="glyphicon glyphicon-search" aria-hidden="true">搜索</span></button>
          </form>

2. 完成视图函数search()
   1. 获取搜索关键字
      q = request.args.get('q’)
   2. 条件查询
      qu = Question.query.filter(Question.title.contains(q)).order_by('-creat_time’)
   3. 加载查询结果：
      return render_template('index.html', question=qu）
      

      #查询
      @app.route('/search/')
      def search():
          qu=request.args.get('title')
          ques=Question.query.filter(
              or_(
                  Question.title.contains(qu),Question.detail.contains(qu)
              )                   #or语句,实现题目和内容都可以搜素
          ).order_by('-create_time')   #按发布时间顺序排序
          return render_template('base.html',questions=ques)

3. 组合条件查询
   from sqlalchemy import or_, and_

#查询
@app.route('/search/')
def search():
    qu=request.args.get('title')
    ques=Question.query.filter(Question.title.contains(qu)).order_by('-create_time')   #按发布时间顺序排序
   return render_template('base.html',questions=ques)

示例：

Lobby.query.filter(

    or_(

        and_(

            Lobby.id == Team.lobby_id,

            LobbyPlayer.team_id == Team.id,

            LobbyPlayer.player_id == player.steamid

        ),

      and_(

            Lobby.id == spectator_table.c.lobby_id,

            spectator_table.c.player_id == player.steamid

        )

    )

)

https://stackoverflow.com/questions/13370993/sqlalchemy-query-and-or-issue

搜素运行结果：打出“英雄” 出现的界面