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  • java集合之HashMap源码学习

       |-- Node<K,V>[] table; // 存数据的结构
            int threshold;
            
        |-- new HashMap<>() {
                // DEFAULT_LOAD_FACTOR = 0.75f
                this.loadFactor = DEFAULT_LOAD_FACTOR; // all other fields defaulted
            }
        |-- put(key, value) {
                Node<K,V>[] tab;
                int n;
                int i; // i = (tab.length - 1) & hash
                boolean isTableEmpty = (tab = table) == null || (n = tab.length) == 0;
                if (isTableEmpty) 
                    n = (tab = resize()).length;
                boolean isValueEmpty = ((p = tab[i = (n - 1) & hash]) == null);
                if (isValueEmpty) 
                    tab[i] = newNode(hash, key, value, null);
                else {
                    // TODO 
                    Node<K,V> e;
                    boolean isEqHashAndKey = p.hash == hash && ((k = p.key) == key || (key != null && key.equals(k));
                    if (isEqHashAndKey)
                        e = p;
                    else if (p instanceof TreeNode)
                        e = ((TreeNode<K,V>)p).putTreeVal(this, tab, hash, key, value);
                    else {
                        for (int binCount = 0; ; ++binCount) {
                            if ((e = p.next) == null) {
                                p.next = newNode(hash, key, value, null);
                                if (binCount >= TREEIFY_THRESHOLD - 1) // -1 for 1st
                                    treeifyBin(tab, hash);
                                break;
                            }
                            if (e.hash == hash &&
                                ((k = e.key) == key || (key != null && key.equals(k))))
                                break;
                            p = e;
                        }
                    }
                    if (e != null) { // existing mapping for key
                        V oldValue = e.value;
                        if (!onlyIfAbsent || oldValue == null)
                            e.value = value;
                        afterNodeAccess(e);
                        return oldValue;
                    }
                }
                ++modCount;
                if (++size > threshold)
                    resize();
            }
        |-- resize() {
                Node<K,V>[] oldTab = table;
                int oldCap = (oldTab == null) ? 0 : oldTab.length;
                int oldThr = threshold;
                int newCap, newThr = 0;
                if (oldCap > 0) {
                    if (oldCap >= MAXIMUM_CAPACITY) { // >= 2的30次方
                        threshold = Integer.MAX_VALUE; // = (2的31次方-1)
                        return oldTab;
                    } else if ((newCap = oldCap << 1) < MAXIMUM_CAPACITY &&
                        oldCap >= DEFAULT_INITIAL_CAPACITY){ // (oldCap x 2) < 2的30次方 && oldCap >= 16
                        newThr = oldThr << 1; // double threshold
                    }
                }
                else if (oldThr > 0) // initial capacity was placed in threshold
                    newCap = oldThr;
                else {               // zero initial threshold signifies using defaults
                    newCap = DEFAULT_INITIAL_CAPACITY;    // 16
                    newThr = (int)(DEFAULT_LOAD_FACTOR * DEFAULT_INITIAL_CAPACITY); // 0.75*16
                }
                if (newThr == 0) {
                    float ft = (float)newCap * loadFactor;
                    newThr = (newCap < MAXIMUM_CAPACITY && ft < (float)MAXIMUM_CAPACITY ?
                              (int)ft : Integer.MAX_VALUE); // 
                }
                threshold = newThr;
                Node<K,V>[] newTab = (Node<K,V>[])new Node[newCap];
                table = newTab;
                if (oldTab != null) {
                    // TODO 
                }
                return newTab;
            }
        |-- get(key) {
                Node<K,V>[] tab; Node<K,V> first, e; int n; K k;
                boolean isExsitsFirst = ((tab = table) != nul && (n = tab.length) > 0 &&
                    (first = tab[(n - 1) & hash]) != null);
                if (isExsitsFirst) {
                    if (first.hash == hash && 
                        ((k = first.key) == key || (key != null && key.equals(k)))) 
                        return first;
                    if ((e = first.next) != null) {
                        if (first instanceof TreeNode)
                            return ((TreeNode<K,V>)first).getTreeNode(hash, key);
                        do {
                            if (e.hash == hash &&
                                ((k = e.key) == key || (key != null && key.equals(k))))
                                return e;
                        } while ((e = e.next) != null);
                    }
                }
            }
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  • 原文地址:https://www.cnblogs.com/ice-line/p/9965724.html
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