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  • bzoj 1012 BST 支持插入,区间最大

    水。。。

      1 /**************************************************************
      2     Problem: 1012
      3     User: idy002
      4     Language: C++
      5     Result: Accepted
      6     Time:1372 ms
      7     Memory:5960 kb
      8 ****************************************************************/
      9  
     10 #include <cstdio>
     11 #include <iostream>
     12 #define fprintf(...)
     13 #define oo 0x3f3f3f3f
     14 #define maxn 200010
     15 using namespace std;
     16  
     17 namespace S {
     18     int pre[maxn], son[maxn][2], siz[maxn], val[maxn], mv[maxn], root, ntot;
     19  
     20     void update( int nd ) {
     21         siz[nd] = siz[son[nd][0]]+siz[son[nd][1]]+1;
     22         mv[nd] = max( val[nd], max( mv[son[nd][0]], mv[son[nd][1]] ) );
     23     }
     24     void rotate( int nd, int d ) {
     25         int p = pre[nd];
     26         int s = son[nd][!d];
     27         int ss = son[s][d];
     28  
     29         son[nd][!d] = ss;
     30         son[s][d] = nd;
     31         if( p ) son[p][ nd==son[p][1] ] = s;
     32         else root = s;
     33  
     34         pre[s] = p;
     35         pre[nd] = s;
     36         if( ss ) pre[ss] = nd;
     37  
     38         update( nd );
     39         update( s );
     40     }
     41     void splay( int nd, int top=0 ) {
     42         while( pre[nd]!=top ) {
     43             int p = pre[nd];
     44             int nl = nd==son[p][0];
     45             if( pre[p]==top ) {
     46                 rotate( p, nl );
     47             } else {
     48                 int pp = pre[p];
     49                 int pl = p==son[pp][0];
     50                 if( nl==pl ) {
     51                     rotate( pp, pl );
     52                     rotate( p, nl );
     53                 } else {
     54                     rotate( p, nl );
     55                     rotate( pp, pl );
     56                 }
     57             }
     58         }
     59     }
     60     int newnode( int p, int v ) {
     61         int nd = ++ntot;
     62         pre[nd] = p;
     63         son[nd][0] = son[nd][1] = 0;
     64         siz[nd] = 1;
     65         mv[nd] = val[nd] = v;
     66         return nd;
     67     }
     68     int find( int pos ) {
     69         int nd = root;
     70         while( 1 ) {
     71             int ls = siz[son[nd][0]];
     72             if( pos<=ls ) {
     73                 nd = son[nd][0];
     74             } else if( pos>=ls+2 ) {
     75                 nd = son[nd][1];
     76                 pos -= ls+1;
     77             } else return nd;
     78         }
     79     }
     80     void init() {
     81         root = ntot = 0;
     82         val[0] = mv[0] = -oo;
     83     }
     84     void add_val( int v ) {
     85         fprintf( stderr, "add_val( %d )
    ", v );
     86         if( !root ) {
     87             root = newnode( 0, v );
     88             return;
     89         }
     90         int nd = root;
     91         while( son[nd][1] ) nd=son[nd][1];
     92         son[nd][1] = newnode( nd, v );
     93         splay( son[nd][1] );
     94     }
     95     int qu_max( int pos ) {
     96         fprintf( stderr, "qu_max( %d )
    ", pos );
     97         int nd = find(pos);
     98         splay( nd );
     99         return max( val[nd], mv[son[nd][1]] );
    100     }
    101 };
    102  
    103 int main() {
    104     int T, mod;
    105     int lastans = 0;
    106  
    107     scanf( "%d%d", &T, &mod );
    108     S::init();
    109     while( T-- ) {
    110         char opt[10];
    111         int v;
    112         scanf( "%s%d", opt, &v );
    113         if( opt[0]=='A' ) {
    114             v += lastans;
    115             v %= mod;
    116             S::add_val( v );
    117         } else {
    118             printf( "%d
    ", lastans=S::qu_max( S::siz[S::root]-v+1 ) );
    119         }
    120     }
    121 }
    View Code
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  • 原文地址:https://www.cnblogs.com/idy002/p/4296134.html
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