django 3种返回json方法
1.手动组装字典返回
from django.http import JsonResponse, HttpResponse
from django.shortcuts import render
from app01.models import Book
# Create your views here.
def get_book(request):
all_book = Book.objects.all()
d = []
for i in all_book:
d.append({'name': i.name})
return JsonResponse(d, safe=False)
2.JsonResponse返回
def get_book2(request):
from django.forms.models import model_to_dict
all_book = Book.objects.all()
d = []
for i in all_book:
d.append(model_to_dict(i)) # <-------针对一个对象()
return JsonResponse(d, safe=False) # 非字典要设置成false
一般自己的系统会从别的系统获取数据, 这里应该也仅限于展示, 所以JsonResponse还是有很多实用场景
def booapi(request):
from django.core.serializers import serialize
book_list = [
{'id': 1, 'name': 'ptyhon'},
{'id': 2, 'name': 'go'},
]
import json
return HttpResponse(json.dumps(book_list), content_type='application/json')
3.django自带的serializers返回
这个好像只能针对queryset操作,即本地db里的数据,不能操作从其他系统api获取到的list ,dict等
def get_book3(request):
from django.core.serializers import serialize
d = serialize('json', Book.objects.all()) # <-------针对一个queryset,[{}, {}]
# return HttpResponse(d)
return HttpResponse(d)
return render(request, 'myapp/index.html', {'foo': 'bar',}, content_type='application/xhtml+xml')
return HttpResponse(t.render(c, request), content_type='application/xhtml+xml')
return HttpResponse(json.dumps(data), content_type='application/json', status=400)
JsonResponse = HttpResponse+content-type
model转dict方法
https://mp.weixin.qq.com/s/7gPLaCESHAB0dLgq7qZq5Q
使用类的__dict__方法
