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  • 学军中学推理社2017届招新试题


    迷失在幽谷中的鸟儿,独自飞翔在这偌大的天地间,却不知自己该飞往何方……

    #include <iostream>
    #include <string.h>
    #include <stdio.h>
    #include <stdlib.h>
    #include <algorithm>
    using namespace std;
    int ab[12]= {0};
    int tw()
    {
        switch(ab[2])
        {
        case 1:
            if(ab[5]==3)return 0;
            break;
        case 2:
            if(ab[5]==4)return 0;
            break;
        case 3:
            if(ab[5]==1)return 0;
            break;
        case 4:
            if(ab[5]==2)return 0;
            break;
        }
        return 1;
    }
    int tr()
    {
        switch(ab[3])
        {
        case 1:
            if(ab[6]!=1&&ab[2]!=1&&ab[4]!=1)return 0;
            break;
        case 2:
            if(ab[6]!=2&&ab[6]!=ab[2]&&ab[6]!=ab[4])return 0;
            break;
        case 3:
            if(ab[2]!=3&&ab[2]!=ab[6]&&ab[2]!=ab[4])return 0;
            break;
        case 4:
            if(ab[4]!=4&&ab[4]!=ab[2]&&ab[4]!=ab[6])return 0;
            break;
        }
        return 1;
    }
    int fo()
    {
        switch(ab[4])
        {
        case 1:
            if(ab[1]==ab[5])return 0;
            break;
        case 2:
            if(ab[2]==ab[7])return 0;
            break;
        case 3:
            if(ab[1]==ab[9])return 0;
            break;
        case 4:
            if(ab[6]==ab[10])return 0;
            break;
        }
        return 1;
    }
    int fi()
    {
        switch(ab[5])
        {
        case 1:
            if(ab[8]==1)return 0;
            break;
        case 2:
            if(ab[4]==2)return 0;
            break;
        case 3:
            if(ab[9]==3)return 0;
            break;
        case 4:
            if(ab[7]==4)return 0;
            break;
        }
        return 1;
    }
    int si()
    {
        switch(ab[6])
        {
        case 1:
            if(ab[2]==ab[4]&&ab[8]==ab[2])return 0;
            break;
        case 2:
            if(ab[1]==ab[6]&&ab[1]==ab[8])return 0;
            break;
        case 3:
            if(ab[3]==ab[10]&&ab[3]==ab[8])return 0;
            break;
        case 4:
            if(ab[5]==ab[9]&&ab[8]==ab[5])return 0;
            break;
        }
        return 1;
    }
    int k[5];
    int big(int n)
    {
        for(int i=1; i<=4; i++)
            if(k[n]>k[i])return 0;
        return 1;
    }
    int se()
    {
        switch(ab[7])
        {
        case 1:
            if(big(3))return 0;
            break;
        case 2:
            if(big(2))return 0;
            break;
        case 3:
            if(big(1))return 0;
            break;
        case 4:
            if(big(4))return 0;
            break;
        }
        return 1;
    }
    int te()
    {
        int t=abs(k[4]-k[1]);
        switch(ab[10])
        {
        case 1:
            if(t==3)return 0;
            break;
        case 2:
            if(t==2)return 0;
            break;
        case 3:
            if(t==4)return 0;
            break;
        case 4:
            if(t==1)return 0;
            break;
        }
        return 1;
    }
    int ei()
    {
        switch(ab[8])
        {
        case 1:
            if(abs(ab[7]-ab[1])!=1)return 0;
            break;
        case 2:
            if(abs(ab[5]-ab[1])!=1)return 0;
            break;
        case 3:
            if(abs(ab[2]-ab[1])!=1)return 0;
            break;
        case 4:
            if(abs(ab[10]-ab[1])!=1)return 0;
            break;
        }
        return 1;
    }
    int ni()
    {
        int a=(ab[1]==ab[6]);
        switch(ab[9])
        {
        case 1:
            if((ab[6]==ab[5])!=a)return 0;
            break;
        case 2:
            if((ab[10]==ab[5])!=a)return 0;
            break;
        case 3:
            if((ab[2]==ab[5])!=a)return 0;
            break;
        case 4:
            if((ab[9]==ab[5])!=a)return 0;
            break;
        }
        return 1;
    }
    int panduan()
    {
        memset(k,0,sizeof(k));
        if(tw())return 0;
        if(tr())return 0;
        if(fo())return 0;
        if(fi())return 0;
        if(si())return 0;
        if(ei())return 0;
        if(ni())return 0;
        for(int i=1; i<=10; i++)
            k[ab[i]]++;
        if(se())return 0;
        sort(k,k+5);
        if(te())return 0;
        return 1;
    }
    int digui(int i)
    {
        if(i==11&&panduan())
            for(int a=1; a<=10; a++)
                printf("%d	%c
    ",a,64+ab[a]);
        else if(i<11)
            for(ab[i]=1; ab[i]<=4; ab[i]++)
                digui(i+1);
        return 0;
    }
    int main()
    {
        printf("answer:
    ");
        digui(1);
        return 0;
    }
    

    暴力枚举,简简单单偷笑

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  • 原文地址:https://www.cnblogs.com/im0qianqian/p/5989460.html
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