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  • POJ 1663:Number Steps

    Number Steps
    Time Limit: 1000MS   Memory Limit: 10000K
    Total Submissions: 13758   Accepted: 7430

    Description

    Starting from point (0,0) on a plane, we have written all non-negative integers 0,1,2, ... as shown in the figure. For example, 1, 2, and 3 has been written at points (1,1), (2,0), and (3, 1) respectively and this pattern has continued. 

    You are to write a program that reads the coordinates of a point (x, y), and writes the number (if any) that has been written at that point. (x, y) coordinates in the input are in the range 0...5000.

    Input

    The first line of the input is N, the number of test cases for this problem. In each of the N following lines, there is x, and y representing the coordinates (x, y) of a point.

    Output

    For each point in the input, write the number written at that point or write No Number if there is none.

    Sample Input

    3
    4 2
    6 6
    3 4

    Sample Output

    6
    12
    No Number

    Source

    你  离  开  了  ,  我  的  世  界  里  只  剩  下  雨  。  。  。

    #include<iostream>
    using namespace std;
    int main()
    {
        int n;
        cin>>n;
        while(n--)
        {
            int a,b;
            cin>>a>>b;
            if(a==b||a-b==2)
            {
                if(a==b)
                {
                    if(a&1)cout<<2*a-1<<endl;
                    else cout<<2*a<<endl;
                }
                else
                {
                    if(b&1)cout<<2*a-3<<endl;
                    else cout<<2*a-2<<endl;
                }
            }
            else cout<<"No Number"<<endl;
        }
        return 0;
    }
    

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  • 原文地址:https://www.cnblogs.com/im0qianqian/p/5989572.html
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