Given a Weather
table, write a SQL query to find all dates' Ids with higher temperature compared to its previous (yesterday's) dates.
For example, return the following Ids for the above Weather table:+---------+------------+------------------+ | Id(INT) | Date(DATE) | Temperature(INT) | +---------+------------+------------------+ | 1 | 2015-01-01 | 10 | | 2 | 2015-01-02 | 25 | | 3 | 2015-01-03 | 20 | | 4 | 2015-01-04 | 30 | +---------+------------+------------------+
+----+ | Id | +----+ | 2 | | 4 | +----+
# Write your MySQL query statement below SELECT W1.Id FROM Weather W1, Weather W2 WHERE TO_DAYS(W1.Date)-TO_DAYS(W2.Date)=1 AND W1.Temperature>W2.Temperature; # 1428 ms