Given a string s, find the longest palindromic substring in s. You may assume that the maximum length of s is 1000.
Example 1:
Input: "babad" Output: "bab" Note: "aba" is also a valid answer.
Example 2:
Input: "cbbd" Output: "bb"
最长回文字串
回文字符串的特征就是轴对称,根据中间字符轴对称,如果字符是偶数个,那么根据中间空字符对称,如果字符是奇数个,那么根据中间字符对称。
对于长度为n的字符,这样的中心点一共有2N-1个。
从中间向两边展开,观察两边的字符是否相同。
class Solution { public: string longestPalindrome(string s) { int n = s.size(); if (n == 0) return ""; string res = s.substr(0, 1); for (int i = 0; i < n-1; ++i) { string s1 = judge(s, i, i); if (s1.size() > res.size()) res = s1; string s2 = judge(s, i, i+1); if (s2.size() > res.size()) res = s2; } return res; } string judge(string s, int i, int j) { while (i >= 0 && j < s.size() && s[i] == s[j]) { i--; j++; } return s.substr(i+1, j-i-1); } };