Binary String Matching

Binary String Matching

描述

Given two strings A and B, whose alphabet consist only ‘0’ and ‘1’. Your task is only to tell how many times does A appear as a substring of B? For example, the text string B is ‘1001110110’ while the pattern string A is ‘11’, you should output 3, because the pattern A appeared at the posit

输入

The first line consist only one integer N, indicates N cases follows. In each case, there are two lines, the first line gives the string A, length (A) <= 10, and the second line gives the string B, length (B) <= 1000. And it is guaranteed that B is always longer than A.

输出

For each case, output a single line consist a single integer, tells how many times do B appears as a substring of A.

样例输入

3
11
1001110110
101
110010010010001
1010
110100010101011 

样例输出

3
0
3 

 
#include <iostream>
#include <string>

using namespace std;

int main()
{
    int n;
    cin>>n;
    while(n--)
    {
        string strA;
        string strB;
        int count = 0;
        cin>>strA;
        cin>>strB;
        int A = strA.size();
        int B = strB.size();
        for(int i=0; i<B; i++)
        {
            if(strB.substr(i, A) == strA)
                count ++;

        }
        cout<<count<<endl;
    }


    return 0;
}