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  • MS SQL Server的COALESCE函数

    MS SQL Server的COALESCE函数是从一系列表达式中返回第一个NOT NULL的值。

    检查[B],[Q],[S],[T],[U]的值:

    检查顺序[B]->[Q]->[S]->[T]->[U],只要一遇上NOT NULL时,即刻返回。

    IF OBJECT_ID('tempdb.dbo.#Part_summary') IS NOT NULL DROP TABLE #Part_summary
    
    CREATE TABLE #Part_summary (    
        [Item] NVARCHAR(40),
        [B]DECIMAL(18,2),
        [Q]DECIMAL(18,2),
        [S]DECIMAL(18,2),
        [T]DECIMAL(18,2),
        [U]DECIMAL(18,2)
    )
    
    INSERT INTO #Part_summary ([Item],[B],[Q],[S],[T],[U])
    VALUES ('098-SSSS1-WS0098-5526',NULl,NULl,500.00,NULl,NULl),
           ('54F-ART43-6545NN-2514',NULl,NULl,934.39,NULl,NULl),
           ('872-RTDE3-Q459PW-2323',NULl,346.43,NULl,452.44,NULl),
           ('B78-F1H2Y-5456UD-2530',234.22,NULl,NULl,115.06,NULl),
           ('I32-GG443-QT0098-0001',NULl,NULl,423.65,NULl,NULl),
           ('I38-AA321-WS0098-0506',470.87,NULl,NULl,NULl,345.41),
           ('K38-12321-5456UD-3493',200.28,NULl,NULl,398.55,NULl),
           ('PO0-7G7G7-JJY098-0077',NULl,871.33,543.00,NULl,NULl),
           ('RVC-43ASE-H43QWW-9753',NULl,564.96,NULl,NULl,555.19),
           ('X3C-SDEWE-3ER808-8764',NULl,607.88,NULl,NULl,NULl)
    
    SELECT [Item],[B],[Q],[S],[T],[U]  FROM #Part_summary
    
    SELECT [Item],COALESCE([B],[Q],[S],[T],[U]) AS [result] FROM #Part_summary
    Source Code

    再列一个例子:

    IF OBJECT_ID('tempdb.dbo.#Part_summary') IS NOT NULL DROP TABLE #Part_summary
    
    CREATE TABLE #Part_summary (    
        [Item] NVARCHAR(40),
        [B]DECIMAL(18,2),
        [Q]DECIMAL(18,2),
        [S]DECIMAL(18,2),
        [T]DECIMAL(18,2),
        [U]DECIMAL(18,2)
    )
    
    INSERT INTO #Part_summary ([Item],[B],[Q],[S],[T],[U])
    VALUES ('54F-ART43-6545NN-2514',NULl,NULl,NULl,NULl,934.39),
           ('872-RTDE3-Q459PW-2323',NULl,NULl,NULl,452.44,NULl),
           ('B78-F1H2Y-5456UD-2530',NULl,NULl,115.06,NULl,NULl),
           ('I32-GG443-QT0098-0001',NULl,607.88,NULl,NULl,NULl),
           ('I38-AA321-WS0098-0506',470.87,NULl,NULl,NULl,NULl)
    
    SELECT [Item],[B],[Q],[S],[T],[U]  FROM #Part_summary
    
    SELECT [Item],COALESCE([B],[Q],[S],[T],[U]) AS [result] FROM #Part_summary
    Source Code
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  • 原文地址:https://www.cnblogs.com/insus/p/10900499.html
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