example:
A -> 1 B -> 2 C -> 3 ... Z -> 26 AA -> 27 AB -> 28
"26进制 -> 10进制" 的转化
class Solution: # @param s, a string # @return an integer def titleToNumber(self, s): d=dict([('A', 1), ('B', 2), ('C', 3),('D',4),('E',5),('F',6),('G',7),('H',8),('I',9),('J',10),('K',11),('L',12),('M',13),('N',14),('O',15),('P',16),('Q',17),('R',18),('S',19),('T',20),('U',21),('V',22),('W',23),('X',24),('Y',25),('Z',26)]); res=0 num_char=len(s) for i in range(len(s)): res=res+d[s[i]]*pow(26,(num_char-i-1)) print(res) return res s=Solution() s.titleToNumber("ZZZ") # "ZZ" 702= 26*26+26