zoukankan      html  css  js  c++  java

  • 【lightoj 1354 IP Checking 来来，，发个巨水的题目玩玩。】

    1354 - IP Checking
    Time Limit: 2 second(s) Memory Limit: 32 MB

    An IP address is a 32 bit address formatted in the following way

    a.b.c.d

    where a, b, c, d are integers each ranging from 0 to 255. Now you are given two IP addresses, first one in decimal form and second one in binary form, your task is to find if they are same or not.

    Input

    Input starts with an integer T (≤ 100), denoting the number of test cases.

    Each case starts with two lines. First line contains an IP address in decimal form, and second line contains an IP address in binary form. In binary form, each of the four parts contains 8 digits. Assume that the given addresses are valid.

    Output

    For each case, print the case number and "Yes" if they are same, otherwise print "No".

    Sample Input

    Output for Sample Input

    2

    192.168.0.100

    11000000.10101000.00000000.11001000

    65.254.63.122

    01000001.11111110.00111111.01111010

    Case 1: No

    Case 2: Yes
    PROBLEM SETTER: JANE ALAM JAN
     
     
     
     
     
     
      1 // Project name : 1354 ( IP Checking ) 
  2 // File name    : main.cpp
  3 // Author       : iCoding
  4 // E-mail       : honi.linux@gmail.com
  5 // Date & Time  : Fri Aug 10 10:01:30 2012
  6 
  7 
  8 #include <iostream>
  9 #include <stdio.h>
 10 #include <string>
 11 #include <cmath>
 12 #include <algorithm>
 13 using namespace std;
 14 
 15 /*************************************************************************************/
 16 /* data */
 17 
 18 int a, b, c, d;
 19 bool iFlag;
 20 string ip;
 21 int tmp;
 22 /*************************************************************************************/
 23 /* procedure */
 24 
 25 void iInit()
 26 {
 27     scanf("%d.%d.%d.%d", &a, &b, &c, &d);
 28     //printf("%d %d %d %d \n", a, b, c, d);
 29     cin >> ip;
 30     iFlag = true;
 31 }
 32 
 33 void iShow(int a, int b)
 34 {
 35     cout << a << " " << b << endl;
 36 }
 37 
 38 bool iIsEqual()
 39 {
 40     tmp = 0;
 41     int iIndex = 0;
 42     while (ip[iIndex] != '.')
 43     {
 44         tmp *= 2;
 45         tmp += (ip[iIndex] - '0');
 46         iIndex++;
 47     }
 48     if (tmp != a)
 49     {
 50         iFlag = false;
 51     }
 52 
 53     tmp = 0;
 54     iIndex++;
 55     while (ip[iIndex] != '.')
 56     {
 57         tmp *= 2;
 58         tmp += (ip[iIndex] - '0');
 59         iIndex++;
 60     }
 61     //iShow(tmp,b);
 62     if (tmp != b)
 63     {
 64         iFlag = false;
 65     }
 66 
 67     tmp = 0;
 68     iIndex++;
 69     while (ip[iIndex] != '.')
 70     {
 71         tmp *= 2;
 72         tmp += (ip[iIndex] - '0');
 73         iIndex++;
 74     }
 75     if (tmp != c)
 76     {
 77         iFlag = false;
 78     }
 79 
 80 
 81     tmp = 0;
 82     iIndex++;
 83     while (ip[iIndex] != '\0')
 84     {
 85         tmp *= 2;
 86         tmp += (ip[iIndex] - '0');
 87         iIndex++;
 88     }
 89     if (tmp != d)
 90     {
 91         iFlag = false;
 92     }
 93 
 94 
 95     return iFlag;
 96 }
 97 
 98 /*************************************************************************************/
 99 /* main */
100 int main()
101 {
102     int iT;
103     scanf("%d", &iT);
104     for (int  iCaseCount = 1; iCaseCount <= iT; iCaseCount++)
105     {
106         printf("Case %d: ", iCaseCount);
107 
108         iInit();
109 
110         if (iIsEqual())
111         {
112             printf("Yes\n");
113         }
114         else
115         {
116             printf("No\n");
117         }
118     }
119     return 0;
120 }
121 
122 // end 
123 // Code by Sublime text 2
124 // iCoding@CodeLab
  • 相关阅读:
    FORM内置系统变量
    linux简单命常用令
    详解EBS接口开发之库存事务处理-物料批次导入
    TRIZ系列-创新原理-5-合并原理
    《Master Opencv...读书笔记》非刚性人脸跟踪 IV (终)
    Echarts折线图
    Redis命令学习-SortedSet（有序集合）
    tky项目第③个半月总结
    Torrent 文件图文解析
    ofbiz SSO 单点登录
  • 原文地址：https://www.cnblogs.com/ismdeep/p/2631351.html
Copyright © 2011-2022 走看看