简单的输入 判断周围上下左右组合的八个方向的雷 然后输出
代码
#include <iostream> #include <memory.h> using namespace std; int n, m; const int N = 110; char mine[N][N]; int addx[8] = { 1,-1,1,-1,1,-1,0,0 }; int addy[8] = { 1,-1,-1,1,0,0,1,-1 }; char GetMineCount(int x, int y) { char ret; if (mine[x][y] == '*') return '*'; int count = 0; for (int i = 0; i < 8; i++) { int newx = x + addx[i]; int newy = y + addy[i]; if (newx >= 0 && newx < n && newy >= 0 && newy < m && mine[newx][newy] == '*') count++; } ret = '0' + count; return ret; } int main() { int idx = 0; while (1) { cin >> n >> m; if (n == 0 || m == 0) return 0; memset(mine, 0, N*N); for (int i = 0; i < n; i++) { for (int j = 0; j < m; j++) { cin >> mine[i][j]; } } if(idx >0 ) cout << endl; cout << "Field #" << ++idx << ":" << endl; for (int x = 0; x < n; x++) { for (int y = 0; y < m; y++) { mine[x][y] = GetMineCount(x, y); cout << mine[x][y]; } cout << endl; } } return 0; }