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  • GPS坐标转百度地图坐标

    百度地图提供了相关API:BMap.Convertor.translate,

    但是使用上存在部分限制:1.次数限制;2.异步回调

    可以用如下方法:

    /**
    *   地图位置计算工具(将GPS坐标转换成百度地图坐标)
    *    参考文档:http://bbs.lbsyun.baidu.com/forum.php?mod=viewthread&tid=10923&qq-pf-to=pcqq.group
    *
    *    使用示例:批量转换坐标位置
    *    
    *    var transferedData = GpsToBaiduPoints(prePoints);
    *    $.each(transferedData,function(index,point){
    *       console.log(point);
    *    });
    *
    *-------------------以下是提供的一个简单的访问接口-------------------------
    *    参数: points:new BMap.Point(lng,lat)的集合
    *    返回值:resultPoints:转换后 BMap.point点集
    *    function GpsToBaiduPoints(points){
    *        var resultPoints = [];
    *        $.each(points,function(index,point){
    *            //世界大地坐标转为百度坐标
    *            var _t = wgs2bd(point.lat,point.lng);
    *            var _BPoint = new BMap.Point(_t[1], _t[0]);
    *            resultPoints.push(_BPoint);
    *        });
    *        return resultPoints;
    *    }
    */
    //默认提供一个接口直接调用
    function GpsToBaiduPoints(points){
        var resultPoints = [];
        $.each(points,function(index,point){
            var _t = wgs2bd(point.lat,point.lng);
            var _BPoint = new BMap.Point(_t[1], _t[0]);
            resultPoints.push(_BPoint);
        });
        return resultPoints;
    }
    
    //////////////////////////////////////////
    //////////////转换核心代码////////////////
    //////////////////////////////////////////
    var pi = 3.14159265358979324;
    var a = 6378245.0;
    var ee = 0.00669342162296594323;
    var x_pi = 3.14159265358979324*3000.0/180.0;
    
    
    //世界大地坐标转为百度坐标
    function wgs2bd(lat,lon) {
        var wgs2gcjR = wgs2gcj(lat, lon);
        var gcj2bdR = gcj2bd(wgs2gcjR[0], wgs2gcjR[1]);
        return gcj2bdR;
    }
    
    function gcj2bd(lat,lon) {
        var x = lon, y = lat;
        var z = Math.sqrt(x * x + y * y) + 0.00002 * Math.sin(y * x_pi);
        var theta = Math.atan2(y, x) + 0.000003 * Math.cos(x * x_pi);
        var bd_lon = z * Math.cos(theta) + 0.0065;
        var bd_lat = z * Math.sin(theta) + 0.006;
        var result = [];
        result.push(bd_lat);
        result.push(bd_lon);
        return result;
    }
    
    function bd2gcj(lat,lon) {
        var x = lon - 0.0065, y = lat - 0.006;
        var z = Math.sqrt(x * x + y * y) - 0.00002 * Math.sin(y * x_pi);
        var theta = Math.atan2(y, x) - 0.000003 * Math.cos(x * x_pi);
        var gg_lon = z * Math.cos(theta);
        var gg_lat = z * Math.sin(theta);
        var result = [];
        result.push(gg_lat);
        result.push(gg_lon);
        return result;
    }
    
    function wgs2gcj(lat,lon) {
        var dLat = transformLat(lon - 105.0, lat - 35.0);
        var dLon = transformLon(lon - 105.0, lat - 35.0);
        var radLat = lat / 180.0 * pi;
        var magic = Math.sin(radLat);
        magic = 1 - ee * magic * magic;
        var sqrtMagic = Math.sqrt(magic);
        dLat = (dLat * 180.0) / ((a * (1 - ee)) / (magic * sqrtMagic) * pi);
        dLon = (dLon * 180.0) / (a / sqrtMagic * Math.cos(radLat) * pi);
        var mgLat = lat + dLat;
        var mgLon = lon + dLon;
        var result = [];
        result.push(mgLat);
        result.push(mgLon);
        return result;
    }
    
    function transformLat(lat,lon) {
        var ret = -100.0 + 2.0 * lat + 3.0 * lon + 0.2 * lon * lon + 0.1 * lat * lon + 0.2 * Math.sqrt(Math.abs(lat));
        ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(lon * pi) + 40.0 * Math.sin(lon / 3.0 * pi)) * 2.0 / 3.0;
        ret += (160.0 * Math.sin(lon / 12.0 * pi) + 320 * Math.sin(lon * pi  / 30.0)) * 2.0 / 3.0;
        return ret;
    }
    
    function transformLon(lat,lon) {
        var ret = 300.0 + lat + 2.0 * lon + 0.1 * lat * lat + 0.1 * lat * lon + 0.1 * Math.sqrt(Math.abs(lat));
        ret += (20.0 * Math.sin(6.0 * lat * pi) + 20.0 * Math.sin(2.0 * lat * pi)) * 2.0 / 3.0;
        ret += (20.0 * Math.sin(lat * pi) + 40.0 * Math.sin(lat / 3.0 * pi)) * 2.0 / 3.0;
        ret += (150.0 * Math.sin(lat / 12.0 * pi) + 300.0 * Math.sin(lat / 30.0 * pi)) * 2.0 / 3.0;
        return ret;
    }
    

      

    参考:

    http://blog.csdn.net/u010989191/article/details/52981878

    http://www.cnblogs.com/guxingzhe/p/5297804.html

    https://my.oschina.net/jack088/blog/391732

    http://www.360doc.com/content/15/0907/15/9261962_497492384.shtml

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  • 原文地址:https://www.cnblogs.com/itfantasy/p/7132296.html
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