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  • oracle故障快速定位

    首先用操作系统命令找出CPU利用率较高的进程ID

    1.查看数据库当前执行的所有SQL和对应的进程ID

    column machine format a16;
    column program format a16;
    select p.spid,s.status,s.machine,p.program,q.sql_text
    from v$session s,v$sqlarea q,v$process p
    where s.sql_address=q.address and s.sql_hash_value=q.hash_value
    and s.paddr=p.addr
    order by 5;

    2.查看当前被锁的表和对应的进程ID---------

    column object_name format a20;
    column program format a30;
    column username format a18;
    column machine format a16;
    select o.object_name, p.spid,l.session_id, s.serial#, s.program,
    s.username, s.machine,s.seconds_in_wait
    from v$locked_object l, all_objects o, v$session s,v$process p
    where o.object_id = l.object_id and s.sid = l.session_id
    and s.paddr=p.addr and s.status='ACTIVE'
    order by 1 desc;

     查看长时间操作的SQL

    column target_desc format a15;
    column message format a50;
    column opname format a12;
    select sid, opname, target_desc,sofar, totalwork, trunc(sofar/totalwork*100,2) || '%' as perwork,
    to_char(start_time,'DD HH24:MI:SS') starttime,elapsed_seconds,message
    from v$session_longops order by 8
    

    -----Top Event------
    select sid,state,wait_class,event from v$session_wait;

    -----历史分析---------- v$active_session_history,DBA_HIST_ACTIVE_SESS_HISTORY
    select to_char(sample_time,'DDHH24MI'),count(*) from
    DBA_HIST_ACTIVE_SESS_HISTORY
    where sample_time>sysdate-1
    group by to_char(sample_time,'DDHH24MI')
    order by 1

    历史不同时段的共同sql

    set pagesize 0
    column sql_id format a14;
    column sql_text format a50;
    select distinct d.sql_id,q.sql_text
    from DBA_HIST_ACTIVE_SESS_HISTORY d,v$sqlarea q
    where sample_time between to_date('02131558','MMDDHH24MI') and to_date('02131559','MMDDHH24MI')
    and d.sql_id=q.sql_id
    intersect
    select distinct d.sql_id,q.sql_text
    from DBA_HIST_ACTIVE_SESS_HISTORY d,v$sqlarea q
    where sample_time between to_date('02131551','MMDDHH24MI') and to_date('02131552','MMDDHH24MI')
    and d.sql_id=q.sql_id
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  • 原文地址:https://www.cnblogs.com/itfriend/p/2351357.html
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