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  • 遗传算法求解最优化问题

    tic
    clc,clear
    load sj.txt %加载敌方100个目标的数据
    x=sj(:,1:2:8);x=x(:);
    y=sj(:,2:2:8);y=y(:);
    sj=[x y];
    d1=[70,40];
    sj0=[d1;sj;d1];
    %距离矩阵d
    sj=sj0*pi/180;
    d=zeros(102);
    for i=1:101
        for j=i+1:102
            temp=cos(sj(i,1)-sj(j,1))*cos(sj(i,2))*cos(sj(j,2))+sin(sj(i,2))*sin(sj(j,2));
            d(i,j)=6370*acos(temp);
        end
    end
    d=d+d';L=102;w=50;dai=100;A=[];
    %通过改良圈算法选取优良父代A
    for k=1:w
        c=randperm(100);
        c1=[1,c+1,102];
        flag=1;
        while flag>0
            flag=0;
            for m=1:L-3
                for n=m+2:L-1
                    if d(c1(m),c1(n))+d(c1(m+1),c1(n+1))<d(c1(m),c1(m+1))+d(c1(n),c1(n+1))
                        flag=1;
                        c1(m+1:n)=c1(n:-1:m+1);
                    end
                end
            end
        end
        A(k,:)=c1;
    end
    
    rand('state',sum(clock));
    %遗传算法实现过程
    for k=1:dai %产生0~1 间随机数列进行编码
        B=A;
        c=randperm(w);
        %交配产生子代B
        for i=1:2:w
            F=2+floor(100*rand(1));
            temp=B(c(i),F:102);
            B(c(i),F:102)=B(c(i+1),F:102);
            B(c(i+1),F:102)=temp;
            [dd,st]=sort(B(c(i),:));
            B(c(i),st)=1:102;
            [dd,st]=sort(B(c(i+1),:));
            B(c(i+1),st)=1:102;
        end
        
        for i=1:w
            c1=B(i,:);
            flag=1;
            while flag>0
                flag=0;
                for m=1:L-3
                    for n=m+2:L-1
                        if d(c1(m),c1(n))+d(c1(m+1),c1(n+1))<d(c1(m),c1(m+1))+d(c1(n),c1(n+1))
                            flag=1;
                            c1(m+1:n)=c1(n:-1:m+1);
                        end
                    end
                end
            end
            B(i,:)=c1;
        end
        
        
        
        %变异产生子代C
        by=find(rand(1,w)<0.1);
        if length(by)==0
            by=floor(w*rand(1))+1;
        end
        C=A(by,:);
        L3=length(by);
        for i=1:L3
            bw=2+floor(100*rand(1,3));
            bw=sort(bw);
            c1=C(i,[1:bw(1)-1,bw(2)+1:bw(3),bw(1):bw(2),bw(3)+1:102]);
            flag=1;
            while flag>0
                flag=0;
                for m=1:L-3
                    for n=m+2:L-1
                        if d(c1(m),c1(n))+d(c1(m+1),c1(n+1))<d(c1(m),c1(m+1))+d(c1(n),c1(n+1))
                            flag=1;
                            c1(m+1:n)=c1(n:-1:m+1);
                        end
                    end
                end
            end
            C(i,:)=c1;
        end
    
        
        G=[A;B;C];
        TL=size(G,1);
        %在父代和子代中选择优良品种作为新的父代
        temp(1:TL)=0;
        for i=1:TL
            for j=1:101
                temp(i)=temp(i)+d(G(i,j),G(i,j+1));
            end
        end
        [dd,st]=sort(temp);
        A=G(st(1:w),:);
    end
    path=A(1,:)
    long=dd(1)
    toc
    xx=sj0(path,1);yy=sj0(path,2);
    plot(xx,yy,'b-o')
    
    %多次运行最小值为:39.24小时
    

      

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  • 原文地址:https://www.cnblogs.com/iupoint/p/9770084.html
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