LOJ#3095. 「SNOI2019」字符串
如果两个串(i,j)比较(i < j),如果离(a_{i})最近的不同的数是(a_{k}),如果(j < k)那么(i)排在(j)前面
否则的话如果(a_{k} < a_{i}),那么(i)排在(j)前
于是写个比较函数扔到sort里就可以了
#include <bits/stdc++.h>
#define fi first
#define se second
#define pii pair<int,int>
#define mp make_pair
#define pb push_back
#define space putchar(' ')
#define enter putchar('
')
#define eps 1e-10
#define MAXN 1000005
#define ba 47
//#define ivorysi
using namespace std;
typedef long long int64;
typedef unsigned int u32;
typedef double db;
template<class T>
void read(T &res) {
res = 0;T f = 1;char c = getchar();
while(c < '0' || c > '9') {
if(c == '-') f = -1;
c = getchar();
}
while(c >= '0' && c <= '9') {
res = res * 10 +c - '0';
c = getchar();
}
res *= f;
}
template<class T>
void out(T x) {
if(x < 0) {x = -x;putchar('-');}
if(x >= 10) {
out(x / 10);
}
putchar('0' + x % 10);
}
int N,id[MAXN],nxt[MAXN];
char s[MAXN];
bool cmp(int a,int b) {
bool f = 0;
if(a > b) {f = 1;swap(a,b);}
if(b < nxt[a]) f ^= 1;
else {
f ^= (s[nxt[a]] < s[a]);
}
return f;
}
void Solve() {
read(N);
scanf("%s",s + 1);
for(int i = 1 ; i <= N ; ++i) {
id[i] = i;
}
nxt[N] = N + 1;
for(int i = N - 1 ; i >= 1 ; --i) {
if(s[i + 1] != s[i]) nxt[i] = i + 1;
else nxt[i] = nxt[i + 1];
}
sort(id + 1,id + N + 1,cmp);
for(int i = 1 ; i <= N ; ++i) {
out(id[i]);space;
}
enter;
}
int main() {
#ifdef ivorysi
freopen("f1.in","r",stdin);
#endif
Solve();
}