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  • 【LOJ】#2114. 「HNOI2015」菜肴制作

    题解

    把所有边反向
    从小到大枚举每个点,把每个点能到达的点挑出来,判完无解后显然是一个DAG,然后在上面求一个编号最大的拓扑序,把这些点全部标记为已选,把每次求得的拓扑序倒序输出

    代码

    
    
    #include <bits/stdc++.h>
    #define fi first
    #define se second
    #define pii pair<int,int>
    #define mp make_pair
    #define pb push_back
    #define enter putchar('
    ')
    #define space putchar(' ')
    #define MAXN 100005
    //#define ivorysi
    using namespace std;
    typedef long long int64;
    typedef long double db;
    typedef unsigned int u32;
    template<class T>
    void read(T &res) {
        res = 0;char c = getchar();T f = 1;
        while(c < '0' || c > '9') {
    	if(c == '-') f = -1;
    	c = getchar();
        }
        while(c >= '0' && c <= '9') {
    	res = res * 10 + c - '0';
    	c = getchar();
        }
        res *= f;
    }
    template<class T>
    void out(T x) {
        if(x < 0) {putchar('-');x = -x;}
        if(x >= 10) out(x / 10);
        putchar('0' + x % 10);
    }
    struct node {
        int to,next;
    }E[MAXN * 2];
    int D,head[MAXN],sumE,N,M,ind[MAXN],L[MAXN],cnt,tims,vis[MAXN];
    void add(int u,int v) {
        E[++sumE].to = v;
        E[sumE].next = head[u];
        head[u] = sumE;
    }
    bool dfs(int u) {
        vis[u] = 1;
        for(int i = head[u] ; i ; i = E[i].next) {
    	int v = E[i].to;
    	if(vis[v] == 1) return false;
    	if(!vis[v]) {if(!dfs(v)) return false;}
        }
        vis[u] = 2;
        return true;
    }
    void dfs1(int u) {
        vis[u] = tims;
        for(int i = head[u]; i ; i = E[i].next) {
    	int v = E[i].to;
    	if(!vis[v]) dfs1(v);
        }
        for(int i = head[u] ; i ; i = E[i].next) {
    	int v = E[i].to;
    	if(vis[v] == tims) ++ind[v];
        }
    }
    priority_queue<int> Q;
    void BFS(int st) {
        Q.push(st);
        cnt = 0;
        while(!Q.empty()) {
    	int u = Q.top();Q.pop();
    	L[++cnt] = u;
    	for(int i = head[u] ; i ; i = E[i].next) {
    	    int v = E[i].to;
    	    if(vis[v] == tims) {
    		--ind[v];
    		if(ind[v] == 0) Q.push(v);
    	    }
    	}
        }
    }
    void Solve() {
        read(N);read(M);
        memset(ind,0,sizeof(ind));
        memset(vis,0,sizeof(vis));
        sumE = 0;memset(head,0,sizeof(head));
        int u,v;
        for(int i = 1 ; i <= M ; ++i) {
    	read(u);read(v);
    	add(v,u);
        }
        for(int i = 1 ; i <= N ; ++i) {
    	if(!vis[i] && !dfs(i)) {
    	    puts("Impossible!");
    	    return;
    	}
        }
        memset(vis,0,sizeof(vis));
        for(int i = 1 ; i <= N ; ++i) {
    	if(!vis[i]) {
    	    ++tims;
    	    dfs1(i);
    	    BFS(i);
    	    for(int j = cnt ; j >= 1 ; --j) {
    		out(L[j]);space;
    	    }
    	}
        }
        enter;
    }
    int main() {
    #ifdef ivorysi
        freopen("f1.in","r",stdin);
    #endif
        read(D);
        while(D--) {
    	Solve();	
        }
    }
    
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  • 原文地址:https://www.cnblogs.com/ivorysi/p/9641443.html
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