Given a sorted linked list, delete all duplicates such that each element appear only once.
For example,
Given 1->1->2
, return 1->2
.
Given 1->1->2->3->3
, return 1->2->3
.
可以用一个指针,也可以用两个指针来完成
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode deleteDuplicates(ListNode head) { if(head == null){ return null; } ListNode cur = head; while(cur.next != null){ if(cur.val == cur.next.val){ cur.next = cur.next.next; }else{ cur = cur.next; } } return head; } }
/** * Definition for singly-linked list. * public class ListNode { * int val; * ListNode next; * ListNode(int x) { val = x; } * } */ public class Solution { public ListNode deleteDuplicates(ListNode head) { if(head == null) return head; ListNode pre = head; ListNode cur = head.next; while(cur != null && pre != null){ if(cur.val == pre.val){ pre.next = cur.next; cur = cur.next; }else{ pre = pre.next; cur = cur.next; } } return head; } }