注意问题的转换,有环,无序,有序,还有他们的包含分界点
其中将字母装换成数字节点很妙
#include <stdio.h>
#include <string.h>
int map[27][27],indegree[27],q[27];
int n,m;
int topsort()
{
int i,num,flag,j,start;
int temp[27],c;
c=0;
flag=1;
for(i=1;i<=n;i++)
temp[i]=indegree[i];
for(i=1;i<=n;i++)
{
num=0;
for(j=1;j<=n;j++)
{
if(temp[j]==0)
{
num++;
start=j;
}
}
if(num==0)
return 0;
if(num>1)
flag=-1;
q[c++]=start;
temp[start]=-1;
for(j=1;j<=n;j++)
{
if(map[start][j]==1)
temp[j]--;
}
}
return flag;
}
int main()
{
char str[4];
int i,j,s;
int singe;
while(scanf("%d%d",&n,&m),n+m)
{
singe=0;
memset(indegree,0,sizeof(indegree));
memset(map,0,sizeof(map));
for(i=1;i<=m;i++)
{
scanf("%s",str);
if(singe)continue;
int x=str[0]-'A'+1;
int y=str[2]-'A'+1;
map[x][y]=1;
indegree[y]++;
s=topsort();
if(s==0)
{
printf("Inconsistency found after %d relations.\n",i);
singe=1;
continue;
}
if(s==1)
{
printf("Sorted sequence determined after %d relations: ",i);
singe=1;
for(j=0;j<n;j++)
printf("%c",q[j]+'A'-1);
printf(".\n");
}
}
if(!singe)
printf("Sorted sequence cannot be determined.\n");
}
return 0;
}