Children’s Queue
Time Limit: 2000/1000 MS (Java/Others) Memory Limit: 65536/32768 K (Java/Others) Total Submission(s): 8194 Accepted Submission(s): 2603
Problem Description
There are many students in PHT School. One day, the headmaster whose name is PigHeader wanted all students stand in a line. He prescribed that girl can not be in single. In other words, either no girl in the queue or more than one girl stands side by side. The case n=4 (n is the number of children) is like FFFF, FFFM, MFFF, FFMM, MFFM, MMFF, MMMM Here F stands for a girl and M stands for a boy. The total number of queue satisfied the headmaster’s needs is 7. Can you make a program to find the total number of queue with n children?
Input
There are multiple cases in this problem and ended by the EOF. In each case, there is only one integer n means the number of children (1<=n<=1000)
Output
For each test case, there is only one integer means the number of queue satisfied the headmaster’s needs.
Sample Input
1
2
3
Sample Output
1
2
4
Author
SmallBeer (CML)
Source
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import java.util.*; import java.math.*; public class Main{ public static void main(String[] args){ Scanner cin = new Scanner(System.in); BigInteger []num = new BigInteger[1010]; num[1] = BigInteger.valueOf(1); num[2] = BigInteger.valueOf(2); num[3] = BigInteger.valueOf(4); num[4] = BigInteger.valueOf(7); for(int i=5; i<1001; i++) num[i] = num[i-1].add(num[i-2].add(num[i-4])); int n; while(cin.hasNext()){ n = cin.nextInt(); System.out.println(num[n]); } } }