A Simple Problem with Integers
Description You have N integers, A1, A2, ... , AN. You need to deal with two kinds of operations. One type of operation is to add some given number to each number in a given interval. The other is to ask for the sum of numbers in a given interval. Input The first line contains two numbers N and Q. 1 ≤ N,Q ≤ 100000. Output You need to answer all Q commands in order. One answer in a line. Sample Input 10 5 1 2 3 4 5 6 7 8 9 10 Q 4 4 Q 1 10 Q 2 4 C 3 6 3 Q 2 4 Sample Output 4 55 9 15 Hint The sums may exceed the range of 32-bit integers.
Source POJ Monthly--2007.11.25, Yang Yi
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#include<iostream> #include<cstdio> #include<cstring> using namespace std; const int maxn=100010; #define lson l,mid,rt<<1 #define rson mid+1,r,rt<<1|1 int n,q; long long sum[maxn<<2]; long long add[maxn<<2]; void Push_Up(int rt) { sum[rt] = sum[rt<<1] + sum[rt<<1|1]; } void Push_Down(int rt,int m) { if (add[rt]) { add[rt<<1] += add[rt]; add[rt<<1|1] += add[rt]; sum[rt<<1] += add[rt] * (m - (m >> 1)); sum[rt<<1|1] += add[rt] * (m >> 1); add[rt] = 0; } } void build(int l,int r,int rt) { add[rt] = 0; if (l == r) { scanf("%I64d",&sum[rt]); return ; } int mid = (l + r) >> 1; build(lson); build(rson); Push_Up(rt); } void update(int L,int R,int c,int l,int r,int rt) { if (L <= l && r <= R) { add[rt] += c; sum[rt] += (long long)c * (r - l + 1); return ; } Push_Down(rt , r - l + 1); int mid = (l + r) >> 1; if (L <= mid) update(L , R , c , lson); if (mid < R) update(L , R , c , rson); Push_Up(rt); } long long query(int L,int R,int l,int r,int rt) { if (L <= l && r <= R) { return sum[rt]; } Push_Down(rt , r - l + 1); int mid = (l + r) >> 1; long long ret = 0; if (L <= mid) ret += query(L , R , lson); if (mid < R) ret += query(L , R , rson); return ret; } int main(){ //freopen("input.txt","r",stdin); while(~scanf("%d%d",&n,&q)){ build(1,n,1); char op[3]; int a,b,c; while(q--){ scanf("%s",op); if (op[0] == 'Q') { scanf("%d%d",&a,&b); printf("%I64d\n",query(a , b , 1 , n , 1)); } else { scanf("%d%d%d",&a,&b,&c); update(a , b , c , 1 , n , 1); } } } return 0; }