select p.*,g.roleName,pg.srcType from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID
这上面那边语句,容易造成数据重复
select distinct p.id,p.*,g.roleName,pg.srcType from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID
加入了distinct 就好很多,但是遇到 了一个sum 求和的问题,没有找到解决方案,手动写的
有兴趣的同学,可以告诉我一下
select distinct p.id,sum(p.gold) from t_gold_pay_add p left join gRole g on p.roleID=g.roleID left join gPay pg on pg.roleID=p.roleID