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  • class Solution(object): def fizzBuzz(self, n): a = [] i = 1 while(i <= n): if(i%15 == 0): a.append("FizzBuzz") elifleetcode day_01

    412. Fizz Buzz

    Write a program that outputs the string representation of numbers from 1 to n.

    But for multiples of three it should output “Fizz” instead of the number and for the multiples of five output “Buzz”. For numbers which are multiples of both three and five output “FizzBuzz”.

    Example:

    n = 15,
    
    Return:
    [
        "1",
        "2",
        "Fizz",
        "4",
        "Buzz",
        "Fizz",
        "7",
        "8",
        "Fizz",
        "Buzz",
        "11",
        "Fizz",
        "13",
        "14",
        "FizzBuzz"
    ]
    

      自己答案:

    class Solution(object):
             def fizzBuzz(self, n):
          a = []
          i = 1
          while(i <= n):
            if(i%15 == 0):
              a.append("FizzBuzz")

            elif(i%3 == 0):
              a.append("Fizz")
            elif(i%5 == 0):
              a.append("Buzz")

            else:
              a.append(str(i))
            i = i + 1
          return a

      经典答案:

    1.

    class Solution(object):
        def fizzBuzz(self, n):
           return [str(i) if (i%3!=0 and i%5!=0) else (('Fizz'*(i%3==0)) + ('Buzz'*(i%5==0))) for i in range(1,n+1)]
    

    2.

    class Solution(object):
        def fizzBuzz(self, n):
    return["Fizz"*(not i%3) + "Buzz"*(not i %5) or str(i) for i in range(1,n+1)]

    自己的答案没有考虑到列表生成式,没有发挥出Python特点:优雅、简介

    列表生成式资料:

    http://www.liaoxuefeng.com/wiki/001374738125095c955c1e6d8bb493182103fac9270762a000/00138681963899940a998c0ace64bb5ad45d1b56b103c48000

     

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  • 原文地址:https://www.cnblogs.com/jackzone/p/6070577.html
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