zoukankan      html  css  js  c++  java
  • poj 1163 The Triangle

    Description

    7
    3 8
    8 1 0
    2 7 4 4
    4 5 2 6 5

    (Figure 1)
    Figure 1 shows a number triangle. Write a program that calculates the highest sum of numbers passed on a route that starts at the top and ends somewhere on the base. Each step can go either diagonally down to the left or diagonally down to the right.

    Input

    Your program is to read from standard input. The first line contains one integer N: the number of rows in the triangle. The following N lines describe the data of the triangle. The number of rows in the triangle is > 1 but <= 100. The numbers in the triangle, all integers, are between 0 and 99. 

    Output

    Your program is to write to standard output. The highest sum is written as an integer.

    Sample Input

    5
    7
    3 8
    8 1 0 
    2 7 4 4
    4 5 2 6 5

    Sample Output

    30

    代码如下
     1 #include <cstdio>
     2 #include <cstdlib>
     3 #include <cstring>
     4 
     5 int tri[102][102];
     6 int sum[102][102];
     7 int dir[][4] = {{1,0},{1,1}};
     8 int n;
     9 
    10 void dfs(int x, int y) {
    11     for(int i = 0; i < 2; i++) {
    12         int tmpx = x + dir[i][0];
    13         int tmpy = y + dir[i][1];
    14         if(tmpx < n && tmpy >= 0 && tmpy <= tmpx) {
    15             if(sum[tmpx][tmpy] < sum[x][y] + tri[tmpx][tmpy]) {
    16                 sum[tmpx][tmpy] = sum[x][y] + tri[tmpx][tmpy];
    17                 dfs(tmpx, tmpy);
    18             }
    19         }
    20     }
    21 }
    22 
    23 int main(int argc, char const *argv[])
    24 {
    25     //freopen("input.txt","r",stdin);
    26     while(scanf("%d",&n) != EOF) {
    27         for(int i = 0; i < n; i++) {
    28             for(int j = 0; j <= i; j++) {
    29                 scanf("%d",&tri[i][j]);    
    30             }
    31         }
    32         memset(sum, 0, sizeof(sum));
    33         sum[0][0] = tri[0][0];
    34         dfs(0,0);
    35         int max = 0;
    36         for(int i = 0; i < n; i++) {
    37             if(max < sum[n-1][i]) {
    38                 max = sum[n-1][i];
    39             }
    40         }
    41         printf("%d
    ",max);
    42     }
    43     return 0;
    44 }

     这个题和3176基本一致,但把数组扩大后在3176上跑却一直WA,不明白为甚吗

    改成dp的代码如下

     1 #include <cstdio>
     2 #include <string>
     3 #include <iostream>
     4 using namespace std;
     5 
     6 int n;
     7 int bow[352][352] = {0};
     8 
     9 int main(int argc, char const *argv[])
    10 {
    11     //freopen("input.txt","r",stdin);
    12     scanf("%d",&n);
    13     for(int i = 0; i < n; i++) {
    14         for(int j = 0; j <= i; j++) {
    15             scanf("%d",&bow[i][j]);
    16         }
    17     } 
    18     for(int i = n-2; i >= 0; i--) {
    19         for(int j = 0; j <= i; j++) {
    20             bow[i][j] = bow[i][j] + max(bow[i+1][j], bow[i+1][j+1]);
    21         }
    22     }
    23     printf("%d
    ",bow[0][0]);
    24     return 0;
    25 }
  • 相关阅读:
    Altium Designer 20下载与安装教程
    推荐一些好用的Chrome插件
    记录生活——三款优秀云笔记的搭配使用
    Sublime Text3的安装以及python开发环境的搭建
    Altium Designer 只导出PCB元器件及标号的PDF文件的方法
    Altium Designer 编译原理图出现has no driving source警告解决办法
    Altium Designer 16 如何分别导出TOP层和BOTTOM层
    HTML学习记录和总结
    AD16/MDK5/CAD2019及2007/Dev-C++/Office2016专业版软件安装包
    Keil5调试过程中遇到的一些警告和错误
  • 原文地址:https://www.cnblogs.com/jasonJie/p/5770442.html
Copyright © 2011-2022 走看看