zoukankan      html  css  js  c++  java
  • HDU_1729_sg函数(dfs)

    Stone Game

    Time Limit: 5000/1000 MS (Java/Others)    Memory Limit: 65535/32768 K (Java/Others)
    Total Submission(s): 3051    Accepted Submission(s): 939


    Problem Description
    This game is a two-player game and is played as follows:

    1. There are n boxes; each box has its size. The box can hold up to s stones if the size is s.
    2. At the beginning of the game, there are some stones in these boxes.
    3. The players take turns choosing a box and put a number of stones into the box. The number mustn’t be great than the square of the number of stones before the player adds the stones. For example, the player can add 1 to 9 stones if there are 3 stones in the box. Of course, the total number of stones mustn’t be great than the size of the box.
    4.Who can’t add stones any more will loss the game.

    Give an Initial state of the game. You are supposed to find whether the first player will win the game if both of the players make the best strategy.
     
    Input
    The input file contains several test cases.
    Each test case begins with an integer N, 0 < N ≤ 50, the number of the boxes.
    In the next N line there are two integer si, ci (0 ≤ ci ≤ si ≤ 1,000,000) on each line, as the size of the box is si and there are ci stones in the box.
    N = 0 indicates the end of input and should not be processed.
     
    Output
    For each test case, output the number of the case on the first line, then output “Yes” (without quotes) on the next line if the first player can win the game, otherwise output “No”.
     
    Sample Input
    3
    2 0
    3 3
    6 2
    2
    6 3
    6 3
    0
     
    Sample Output
    Case 1: Yes
    Case 2: No
     
    题意:n个盒子,每个容量为si,已装入ci个石子,两个玩家,分别往盒子中放入石子,每次放入的石子数量不能超过盒子中石子数量的平方,没有盒子可以放的玩家败。
    最开始想用之前的模版来做,求sg值,但是这道题的“点数”为1000000,用之前的模版显然超时,所以果断看了题解,大牛们用的是dfs求每个点的sg值。
     
    #include<iostream>
    #include<cstdio>
    #include<cstring>
    #include<algorithm>
    #include<cmath>
    #include<vector>
    using namespace std;
    #define N 1000005
    
    int Sg(int c,int s)
    {
        int t=sqrt(s);
        while(t*t+t>=s)
            t--;
        if(c>t)
            return s-c;
        else
            return Sg(c,t);
    }
    
    int main()
    {
        int n,cnt=0;
        while(scanf("%d",&n)!=EOF&&n)
        {
            int s,c,res=0;
            while(n--)
            {
                scanf("%d%d",&s,&c);
                res^=Sg(c,s);
            }
            printf("Case %d:
    ",++cnt);
            if(res)
                printf("Yes
    ");
            else
                printf("No
    ");
        }
        return 0;
    }
  • 相关阅读:
    React 中使用 pdf.js 将 pdf 转换成图片
    html2pdf 无法导出 html 中 img 图片的解决方法
    js-xlsx 实现前端 Excel 导出(支持多 sheet)
    React 项目引入 Dva
    项目构建分析和 webpack 优化实践
    《写给大家看的设计书》读书笔记
    2019年六月前端面试经验总结
    UITableView .grouped 类型去除顶部间距
    Ant Design Upload 组件上传文件到云服务器
    家庭动物园下载链接
  • 原文地址:https://www.cnblogs.com/jasonlixuetao/p/5703347.html
Copyright © 2011-2022 走看看