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  • AOJ 0005 GCD and LCM

    Write a program which computes the greatest common divisor (GCD) and the least common multiple (LCM) of given a and b.

    Input

    Input consists of several data sets. Each data set contains a and b separated by a single space in a line. The input terminates with EOF.

    Constraints

    • 0 < a, b ≤ 2,000,000,000
    • LCM(a, b) ≤ 2,000,000,000
    • The number of data sets ≤ 50

    Output

    For each data set, print GCD and LCM separated by a single space in a line.

    Sample Input

    8 6
    50000000 30000000
    

    Output for the Sample Input

    2 24
    10000000 150000000

    #include <iostream>
    #include <cstdio>
    #include <cstring>
    #include <cstdlib>
    #include <algorithm>
    #define MAX_N 1001
    using namespace std;
    typedef long long LL;
    
    LL gcd(LL a,LL b) {
        if(b == 0)return a;
        return gcd(b,a % b);
    }
    LL lcm(LL a,LL b) {
        return a / gcd(a,b) * b;
    }
    int main(){
        LL a,b;
        while(~scanf("%lld%lld",&a,&b)) {
            printf("%lld %lld
    ",gcd(a,b),lcm(a,b));
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jaszzz/p/12691500.html
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