package com.jm.label.tools;
import java.util.Map;
import java.util.TreeMap;
import java.util.regex.Matcher;
import java.util.regex.Pattern;
/**
* 读取字符串中的数字和小数
* @author JM.H
*
*/
public class DigitUtil {
public static String getNumber(String str){
Pattern p = Pattern.compile("(\d+)");
Matcher m = p.matcher(str); String result = "";
if (m.find()) {
Map<Integer, String> map = new TreeMap<Integer, String>();
Pattern p2 = Pattern.compile("(\d+\.\d+)");
m = p2.matcher(str); //遍历小数部分
while (m.find()) {
result = m.group(1) == null ? "" : m.group(1);
int i = str.indexOf(result);
String s = str.substring(i, i + result.length());
map.put(i, s); //排除小数的整数部分和另一个整数相同的情况下,寻找整数位置出现错误的可能,还有就是寻找重复的小数 // 例子中是排除第二个345.56时第一个345.56产生干扰和寻找整数345的位置时,前面的小数345.56会干扰
str = str.substring(0, i) + str.substring(i + result.length()); } //遍历整数
Pattern p3 = Pattern.compile("(\d+)");
m = p3.matcher(str);
while (m.find()) {
result = m.group(1) == null ? "" : m.group(1); int i = str.indexOf(result); //排除jia567.23.23在第一轮过滤之后留下来的jia.23对整数23产生干扰
// System.out.println(String.valueOf(str.charAt(i)));
if (String.valueOf(str.charAt(i)).equals(".")) { //将这个字符串删除
str = str.substring(0, i - 1) + str.substring(i + result.length());
continue;
}
String s = str.substring(i, i + result.length());
map.put(i, s);
str = str.substring(0, i) + str.substring(i + result.length());
}
result = "";
for (Map.Entry<Integer, String> e : map.entrySet()) {
result += e.getValue() + ",";
}
result = result.substring(0, result.length()-1);
}
else {
result = "";
}
// System.out.println(result);
String[] split = result.split(","); //
String resultRtr = split[split.length-1]; //
return resultRtr;
}
}