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  • LeetCode刷题:Reverse Words in a String(翻转字符串中的单词)

    题目

    Given an input string, reverse the string word by word.

    For example,
    Given s = "the sky is blue",
    return "blue is sky the".

    click to show clarification.

    Clarification:

    • What constitutes a word?
      A sequence of non-space characters constitutes a word.
    • Could the input string contain leading or trailing spaces?
      Yes. However, your reversed string should not contain leading or trailing spaces.
    • How about multiple spaces between two words?
      Reduce them to a single space in the reversed string.

    分析

    (1) 去除首尾空格和去除字符串中多余的空格,计划用两个函数实现;
    (2) 翻转整个字符串
    (3) 依次将每个单词翻转

    代码

    #include <iostream>
    #include <string>
    #include <cwctype>
    #include <vector>
    
    using namespace std;
    
    // 去除字符串首尾的空格
    string& trim(string &s)
    {
    	if(s.empty())
    		return s;
    
    	string::iterator iter;
    	for(iter = s.begin(); iter != s.end()&& iswspace(*iter++););
    	s.erase(s.begin(),--iter);
    
    	for(iter = s.end(); iter != s.begin()&& iswspace(*--iter););
    	s.erase(++iter,s.end());
    
    	return s;
    }
    
    // 翻转字符串中的某一段子串
    void reverseString(string &s, int begin, int end)
    {
    	for(; begin < end; begin++,end--)
    	{
    		char temp = s[begin];
    		s[begin] = s[end];
    		s[end] = temp;
    	}
    }
    
    // 删除单词之间多余的空格
    void delete_mult_spaces(string &s)
    {
    	string::iterator blank;
    	string::iterator iter = s.begin();
    	while(iter != s.end())
    	{
    		if(iswspace(*iter))
    		{
    			blank = iter + 1;
    			while(iswspace(*blank))
    				s.erase(blank);
    			iter = blank;
    		}
    		iter++;
    	}
    }
    
    void reverseWords(string &s)
    {
    	if (s.empty())
    		return;
    
    	s = trim(s);
    	delete_mult_spaces(s);
    
    	reverseString(s, 0, s.length()-1);
    
    	int wbegin,wend;
    	wbegin = wend = 0;
    	for(size_t i = 0; i < s.length(); i++)
    	{
    		if(s[i] == ' ')
    		{
    			reverseString(s,wbegin,wend-1);
    			wbegin = wend + 1;
    		}
    		wend++;
    
    		// deal with the last word
    		if(i == s.length()-1)
    			reverseString(s,wbegin,wend-1);
    	}
    }
    
    int main()
    {
    	vector<string> strs;
    	strs.push_back("the sky is blue");
    	strs.push_back("   the sky is blue");
    	strs.push_back("the sky is blue   ");
    
    	strs.push_back("the   sky is blue");
    	strs.push_back("  the sky   is   blue   ");
    	strs.push_back("");
    
    	vector<string>::iterator iter;
    	for(iter = strs.begin(); iter != strs.end(); iter++)
    	{
    		reverseWords(*iter);
    		cout  << *iter << endl;
    	}
    	return 0;
    }


    参考


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  • 原文地址:https://www.cnblogs.com/javaadu/p/11742637.html
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