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  • URAL 1601. AntiCAPS (strings)

    1601. AntiCAPS

    Time limit: 0.5 second
    Memory limit: 64 MB
    The blonde Angela has a new whim: internet chats. Of course, as any blonde, shewrites her messages using the upper case. You are the moderator of Angela'sfavorite chat and you're fed up with her upper-case messages. The problemis that Angela does not respond to your warnings. You decided to write a simpleantiCAPS corrector, which would make Angela's messages readable.
    Problem illustration
    The correction rules are very simple:
    1. Sentences in a message consist of words, spaces and punctuation marks.
    2. Words consist of English letters.
    3. Sentences end with a full stop, exclamation mark, or question mark.
    4. The first word of each sentence must start with a capital letter, and all otherletters of the sentence must be lowercase.

    Input

    You are given Angela's message, which consists of uppercase English letters,spaces, line breaks and punctuation marks: full stops, commas, dashes, colons, exclamationand question marks. Total length of message is not exceeding 10000 symbols.

    Output

    Output the corrected message.

    Sample

    input output
    HI THERE!
    HOW DID YOU KNOW I AM A BLONDE?

    Hi there!
    How did you know i am a blonde?

    Problem Author: Denis Musin
    Problem Source: IX USU Open Personal Contest (March 1, 2008)




    解析:注意两点:

    1.每一个句子以‘.’,‘?’和‘!’结尾。每一个句子开头字符都要换成大写。

    2.换行不算句子结尾的标志。


    下面提供两组測试例子:

    input1:
    HELLO. I AM ANJELA! AND YOU?
    I AM BLONDE.

    output1:
    Hello. I am anjela! And you?


    I am blonde.


    input2:

    HHHHHHHHHH? SDSDFSDF! SFSDF. SDFAF
    HKLLKSDJOI


    output2:

    Hhhhhhhhhh? Sdsdfsdf! Sfsdf. Sdfaf

    hkllksdjoi



    AC代码:

    #include <bits/stdc++.h>
    using namespace std;
    
    int main(){
        #ifdef sxk
            freopen("in.txt", "r", stdin);
        #endif // sxk
    
        string s;
        int flag = 1;
        while(getline(cin, s)){
            int n = s.size();
            for(int i=0; i<n; i++){
                if(flag){
                    if(s[i] >= 'A' && s[i] <= 'Z') flag = 0;
                }
                else{
                    if(s[i] >= 'A' && s[i] <= 'Z') s[i] += ('a' - 'A');
                    else if(s[i] == '.' || s[i] == '?' || s[i] == '!') flag = 1;
                }
            }
            cout<<s<<endl;
        }
        return 0;
    }
    


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  • 原文地址:https://www.cnblogs.com/jhcelue/p/6908106.html
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