zoukankan      html  css  js  c++  java
  • Wannafly挑战赛1 C MMSet2 虚树

    题目链接:https://www.nowcoder.com/acm/contest/15/C

    思路:虚树,取两点间的lca,构造成一颗新的树;求(直径+1)/2即可

    #pragma comment(linker, "/STACK:1024000000,1024000000")
    #include<iostream>
    #include<cstdio>
    #include<cmath>
    #include<string>
    #include<queue>
    #include<algorithm>
    #include<stack>
    #include<cstring>
    #include<vector>
    #include<list>
    #include<set>
    #include<map>
    #include<bitset>
    #include<time.h>
    using namespace std;
    #define LL long long
    #define pi (4*atan(1.0))
    #define eps 1e-8
    #define bug(x)  cout<<"bug"<<x<<endl;
    const int N=3e5+10,M=1e6+10,inf=1e9+7,MOD=1e9+7;
    const LL INF=1e18+10,mod=1e9+7;
    
    struct edge
    {
        int v,next;
    }edge[N<<1];
    int head[N],fa[N][20],edg,deep[N];
    int in[N],out[N],tot;
    void init()
    {
        memset(head,-1,sizeof(head));
        edg=0;tot=0;
    }
    void add(int u,int v)
    {
        edg++;
        edge[edg].v=v;
        edge[edg].next=head[u];
        head[u]=edg;
    }
    void dfs(int u,int fat)
    {
        tot++;
        in[u]=tot;
        for (int i=1; i<=19 ;i++)
            fa[u][i] = fa[fa[u][i-1]][i-1];
        for (int i=head[u];i!=-1;i=edge[i].next)
        {
            int v=edge[i].v;
            if(v==fat) continue;
            deep[v]=deep[u]+1;
            fa[v][0]=u;
            dfs(v,u);
        }
        out[u]=tot;
    }
    int RMQ_LCA(int x,int y) {
        if(deep[x]<deep[y]) swap(x,y);
        int d=deep[x]-deep[y];
        for (int i=0; i<=19 ;i++)
            if((1<<i)&d) x=fa[x][i];
        for (int i=19; i>=0 ;i--) {
            if(fa[x][i]!=fa[y][i]) {
                x=fa[x][i];y=fa[y][i];
            }
        }
        if(x==y) return x;
        else return fa[x][0];
    }
    
    
    int h[M],ans,far,pos;
    struct f
    {
        int v,w,nex;
    }edge2[N<<1];
    int head2[N],edg2;
    void add2(int u,int v,int w)
    {
        edge2[++edg2]=(f){v,w,head2[u]};
        head2[u]=edg2;
    }
    bool cmp(int u, int v) {
        return in[u] < in[v];
    }
    bool check(int u, int v) {
        return in[u] <= in[v] && in[v] <= out[u];
    }
    int build(int A[], int tot) {
        std::sort(A + 1, A + 1 + tot, cmp);
        for(int i = 2, old_tot = tot; i <= old_tot; i++) {
            A[++tot] = RMQ_LCA(A[i - 1], A[i]);
        }
        std::sort(A + 1, A + 1 + tot, cmp);
        tot = std::unique(A + 1, A + 1 + tot) - A - 1;
    
        std::stack<int> S; S.push(A[1]);
        for(int i = 2; i <= tot; i++) {
            while(!S.empty() && !check(S.top(), A[i])) S.pop();
            int u = S.top(), v = A[i];
            add2(u,v,deep[v]-deep[u]);
            add2(v,u,deep[v]-deep[u]);//u, v, deep[v] - deep[u]);
            S.push(v);
        }
        return tot;
    }
    void dfs1(int u,int fa,int val)
    {
        if(val>far)far=val,pos=u;
        for(int i=head2[u];i!=-1;i=edge2[i].nex)
        {
            int v=edge2[i].v;
            int w=edge2[i].w;
            if(v==fa)continue;
            dfs1(v,u,val+w);
        }
    }
    void dfs2(int u,int fa,int val)
    {
        ans=max(ans,val);
        for(int i=head2[u];i!=-1;i=edge2[i].nex)
        {
            int v=edge2[i].v;
            int w=edge2[i].w;
            if(v==fa)continue;
            dfs2(v,u,w+val);
        }
    }
    int main()
    {
        init();
        memset(head2,-1,sizeof(head2));
        int n;
        scanf("%d",&n);
        for(int i=1;i<n;i++)
        {
            int u,v;
            scanf("%d%d",&u,&v);
            add(u,v);add(v,u);
        }
        dfs(1,0);
        int q;
        scanf("%d",&q);
        while(q--)
        {
            edg2=far=pos=ans=0;
            int t;
            scanf("%d",&t);
            for(int i=1;i<=t;i++)
                scanf("%d",&h[i]);
            t = build(h, t);
            dfs1(h[1],0,0);
            dfs2(pos,0,0);
            printf("%d
    ",(ans+1)/2);
            for(int i=1;i<=t;i++)
            head2[h[i]]=-1;
        }
        return 0;
    }

  • 相关阅读:
    CodeForces
    CodeForces
    sort自定义cmp函数
    The 2015 China Collegiate Programming Contest Sudoku
    G
    docker
    在容器内获取Pod信息(Downward API)
    k8s Pod定义详解
    Pod和容器的生命周期管理
    GoAccess日志分析工具
  • 原文地址:https://www.cnblogs.com/jhz033/p/7676795.html
Copyright © 2011-2022 走看看