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  • python实现两个升序链表合并

     1 # Definition for singly-linked list.
     2 class ListNode:
     3     def __init__(self, x):
     4         self.val = x
     5         self.next = None
     6 
     7 
     8 class Solution:
     9     def mergeTwoLists(self, l1: ListNode, l2: ListNode) -> ListNode:
    10 
    11         new = ListNode('head')
    12         new_cur = new
    13         while l1 is not None and l2 is not None:
    14             if l1.val <= l2.val:
    15                 new_cur.next = l1
    16                 new_cur = new_cur.next
    17                 l1 = l1.next
    18             else:
    19                 new_cur.next = l2
    20                 new_cur = new_cur.next
    21                 l2 = l2.next
    22 
    23         if l1 is None:
    24             new_cur.next = l2
    25         else:
    26             new_cur.next = l1
    27 
    28         return new.next
    29 
    30 
    31 def Init_node(s: str) -> ListNode:
    32     s = s.split('->')
    33     head_node = ListNode('head')
    34 
    35     for i in s:
    36         new_node = ListNode(int(i))
    37         cur_node = head_node
    38         while cur_node.next is not None:
    39             cur_node = cur_node.next
    40         cur_node.next = new_node
    41 
    42     return head_node.next
    43 def show_node(node:ListNode):
    44     while node is not None:
    45         print(node.val,end=' ')
    46         node = node.next
    47     print('')
    48 
    49 if __name__ == '__main__':
    50 
    51     s1 = '1->2->4'
    52     s2 = '1->3->4'
    53     list_node_1 = Init_node(s1)
    54     list_node_2 = Init_node(s2)
    55 
    56     solu = Solution()
    57     merge = solu.mergeTwoLists(list_node_1, list_node_2)
    58     show_node(merge)
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  • 原文地址:https://www.cnblogs.com/jiangnanyanyuchen/p/12681128.html
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