zoukankan      html  css  js  c++  java
  • 结合两张表person和address

    Table: Person

    +-------------+---------+
    | Column Name | Type    |
    +-------------+---------+
    | PersonId    | int     |
    | FirstName   | varchar |
    | LastName    | varchar |
    +-------------+---------+
    PersonId is the primary key column for this table.
    

    Table: Address

    +-------------+---------+
    | Column Name | Type    |
    +-------------+---------+
    | AddressId   | int     |
    | PersonId    | int     |
    | City        | varchar |
    | State       | varchar |
    +-------------+---------+
    AddressId is the primary key column for this table.



    为报表编写一个SQL查询,为Person表中的每个人提供以下信息,而不管这些人是否有地址:
    FirstName ,LastName,City ,State


    根据条件不管这些人是否有地址,如果用inner join 那么在地址表中,没用地址的人们将不会出现结果中。所以用左外连接。
    select p.FirstName,p.lastname,a.city,a.state from person p left join address a on p.personId = a.personId
    因为查询字段在两张表中是唯一的,所以可以省略表前缀,写成
    select FirstName ,LastName ,city ,state from person left join address on Person.personId = address.personId
  • 相关阅读:
    codeforces 1012C
    openjudge 6045:开餐馆
    openjudge 7624:山区建小学
    codevs 1040 统计单词个数
    openjudge9267:核电站
    openjudge7624:山区建小学
    bzoj3224:普通平衡树
    洛谷1137:旅行计划
    洛谷1095:守望者的逃离
    校内模拟赛:确定小组
  • 原文地址:https://www.cnblogs.com/jiangshengxiang/p/8420776.html
Copyright © 2011-2022 走看看