第一步很关键，给byte数组赋值，
byte tzi[2][44] =
{
0xD0,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
0x94,0x02,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,0x00,
};必须是以0x的方式开头，表示类型为字节，否则以L“”，这种赋值，会变为ASCII码的形式，
将byte* 赋值给byte* ，利用memcpy(),进行赋值即可。
将TChar*赋值给 byte*
int StrToBin(TCHAR* inWord, BYTE* OutBin, int source_len)
{
int t;
int t2;
int count = 0;
BYTE temBin[2];
temBin[0] = 1;
temBin[1] = 1;
if (source_len < 1)
return 0;
for(t = 0 ;t < source_len; t ++)
{
t2 = inWord[t];
if( t2 > 127 )
{
temBin[0] = t2 >> 8 ;/// 256;
temBin[1] = t2;
OutBin[count] = temBin[0];
count += 1;
OutBin[count] = temBin[1];
count += 1;
}
else
{
OutBin[count] = t2;
count += 1;
}
}
return count;
}