1.continue语句,1至20内奇数累加和
#include<iostream> using namespace std; void main(){ int i=0; int sum=0; while(i<20){ i++; if(i%2==0) continue; else sum+=i; cout<<"当前i的值为"<<i<<" sum的值为"<<sum<<endl; } system("pause"); }
2.break语句,1至20累加和
#include<iostream> using namespace std; void main(){ int i=0; int sum=0; while(i<50){ i++; if(i==21) break; else sum+=i; cout<<"当前i的值为"<<i<<" sum的值为"<<sum<<endl; } system("pause"); }