zoukankan      html  css  js  c++  java
  • LeetCode--链表1-单链表

    LeetCode--链表1-单链表

    单链表模板

    1. 初始化
    2. 头部插入
    3. 尾部插入
    4. 删除节点
    5. Index插入
    6. Index返回对应的节点指针和val值
    class MyLinkedList {
    
    private:
        // 定义单链表的节点
        struct ListNode
        {
            int val;
            ListNode* next;
            ListNode(int x): val(x) , next(nullptr){}
        };
        ListNode* head;
    
    public:
        /** Initialize your data structure here. */
        MyLinkedList() : head(nullptr) {}
        
        /** Get the value of the index-th node in the linked list. If the index is invalid, return -1. */
        int get(int index) {
            if( head == nullptr )
                return -1;
            if( index <= 0 )
                return head->val;
            int count = 0 ; 
            ListNode* p = head;
            while( p && count < index )
            {
                p = p->next;
                count ++;
            }
            if(p)
                return p->val;
            else 
                return -1;
        }
        
        // 在链表头部插入节点
        void addAtHead(int val) {
            ListNode* node = new ListNode(val);
            if( head == nullptr)
            {
                head = node;
                return;
            }
            node->next = head;
            head = node;
        }
        
        // 在链表尾部插入节点
        void addAtTail(int val) {
            ListNode* node = new ListNode(val);
            // 链表为空 就返回
            if(head == nullptr)
            {
                head == node;
                return;
            }
    
            ListNode* p = head;
            while( p->next )
            {
                p = p->next;
            }
            p->next = node;
        }
        
        /** Add a node of value val before the index-th node in the linked list. If index equals to the length of linked list, the node will be appended to the end of linked list. If index is greater than the length, the node will not be inserted. */
        void addAtIndex(int index, int val) {
            ListNode* node = new ListNode(val);
            if(index <= 0)
                addAtHead(val);
            int i = 0;
            ListNode* p = head;
            while(p && i<index - 1)
            {
                p=p->next;
                ++i;
            }
            if(p)
            {
                node->next = p->next;
                p->next = node;
            }
    
        }
        
        /** Delete the index-th node in the linked list, if the index is valid. */
        void deleteAtIndex(int index) {
            if( head==nullptr)
                return ;
            if( index==0 )
            {
                ListNode* p = head;
                head = head->next;
                delete p;
                return;
            }
            ListNode* ps = finder(index-1);
            ListNode* p = finder(index);
            if( p && ps)
            {
                ps->next = p->next;
                return;
            }
            else{
                ps->next = nullptr;
                return ;
            }
            
        }
    
        // 给定下标,返回节点的指针 
        ListNode* finder (int index)
        {
            if( head == nullptr)
                return nullptr;
            if( index <= 0 )
                return head;
            int count = 0 ;
            ListNode* p = head;
            while ( p && count < index)
            {
                p = p->next;
                count ++;
            }
            if(p)
                return p;
            else 
                return nullptr;
        }
    };
    
    /**
     * Your MyLinkedList object will be instantiated and called as such:
     * MyLinkedList* obj = new MyLinkedList();
     * int param_1 = obj->get(index);
     * obj->addAtHead(val);
     * obj->addAtTail(val);
     * obj->addAtIndex(index,val);
     * obj->deleteAtIndex(index);
     */
    
    干啥啥不行,吃饭第一名
  • 相关阅读:
    jquery中选择块并改变属性值的方法
    Bash Shell中Shift用法分享
    linux批量备份服务器配置文件和目录的脚本
    [Java开发之路](8)输入流和输出流
    cf 251 B Playing with Permutations 暴力 分类讨论
    CSS改变字体下划线颜色
    DICOM:C-GET服务
    Android平台录音音量计的实现
    【BZOJ】2186 沙拉公主的困惑
    【php】global的使用与php的全局变量
  • 原文地址:https://www.cnblogs.com/jiangxinyu1/p/12285004.html
Copyright © 2011-2022 走看看