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  • HDU 1171

    母函数简单题

     1 #include <iostream>
     2 #include <cstdio>
     3 using namespace std;
     4 
     5 const int MAX=130000;
     6 int c1[MAX],c2[MAX];
     7 
     8 struct {
     9     int val,num;
    10 }thing[55];
    11 int n;
    12 
    13 int main(){
    14     while(scanf("%d",&n)!=EOF){
    15         if(n<0) break;
    16         int sum=0,tmp;
    17         for(int i=1;i<=n;i++){
    18             scanf("%d%d",&thing[i].val,&thing[i].num);
    19             sum+=(thing[i].val*thing[i].num);
    20         }
    21         tmp=sum/2;
    22         for(int i=0;i<=tmp;i++)
    23         c1[i]=c2[i]=0;
    24         for(int i=0,k=0; i<=tmp&&k<=thing[1].num; i+=thing[1].val,k++)
    25         c1[i]=1;
    26         for(int i=2;i<=n;i++){
    27             for(int j=0;j<=tmp; j++){
    28                 if(c1[j]>=1){
    29                     for(int k=0,p=0; k+j<=tmp&&p<=thing[i].num; k+=thing[i].val,p++){
    30                         c2[j+k]+=c1[j];
    31                     }
    32                 }
    33             }
    34             for(int j=0;j<=tmp;j++){
    35                 c1[j]=c2[j]; c2[j]=0;
    36             }
    37         }
    38         for(int i=tmp;i>=0;i--){
    39             if(c1[i]){
    40                 printf("%d %d
    ",sum-i,i);
    41                 break;
    42             }
    43         }
    44     }
    45     return 0;
    46 }
    View Code
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  • 原文地址:https://www.cnblogs.com/jie-dcai/p/3796820.html
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