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  • HDU 3007

    基本小圆覆盖模板题

    #include <iostream>
    #include <algorithm>
    #include <cmath>
    using namespace std;
    int X,Y; int n;
    const double eps=0.00000001;
    struct point{
        double x,y;
    }p[550];
     
    struct Circle{
        point cent;
        double r;
    }cir;
     
    double dist(point x, point y){
        double a=x.x-y.x;
        double b=x.y-y.y;
        return sqrt(a*a+b*b);
    }
     
    double triangleArea(point t1, point t2, point t3){
        point p1,p2;
        p1.x=t2.x-t1.x; p1.y=t2.y-t1.y;
        p2.x=t3.x-t1.x; p2.y=t3.y-t1.y;
        return fabs(p1.x*p2.y-p1.y*p2.x)/2;
    }
     
    Circle triangleCircle(point t1, point t2, point t3){
        Circle tmp;
        double a=dist(t1,t2);
        double b=dist(t2,t3);
        double c=dist(t3,t1);
        tmp.r=a*b*c/triangleArea(t1,t2,t3)/4;
        double xa,ya,xb,yb,xc,yc;
        double c1,c2;
        xa=t1.x; ya= t1.y;
        xb=t2.x; yb= t2.y;
        xc=t3.x; yc= t3.y;
        c1=(xa*xa+ya*ya-xb*xb-yb*yb)/2;
        c2=(xa*xa+ya*ya-xc*xc-yc*yc)/2;
        tmp.cent.x=(c1*(ya-yc)-c2*(ya-yb))/((xa-xb)*(ya-yc)-(xa-xc)*(ya-yb));
        tmp.cent.y=(c1*(xa-xc)-c2*(xa-xb))/((ya-yb)*(xa-xc)-(ya-yc)*(xa-xb));
        return tmp;
    }
    
    void slove(){
        random_shuffle(p,p+n);
        cir.cent=p[0];
        cir.r=0;
        for(int i=1;i<n;i++){
            if(dist(cir.cent,p[i])>cir.r){
                cir.cent=p[i]; cir.r=0;
                for(int j=0;j<i;j++){
                    if(dist(cir.cent,p[j])>cir.r){
                        cir.cent.x=(p[i].x+p[j].x)/2;
                        cir.cent.y=(p[i].y+p[j].y)/2;
                        cir.r=dist(p[i],p[j])/2;
                        for(int k=0;k<j;k++){
                            if(dist(cir.cent,p[k])>cir.r){
                                cir=triangleCircle(p[i],p[j],p[k]);
                            }
                        }
                    }
                }
            }
        }
    }
    
    int main (){
        while(scanf("%d",&n),n){
            for(int i=0;i<n;i++){
                scanf("%lf%lf",&p[i].x,&p[i].y);
            }
            slove();
            printf("%0.2lf %0.2lf ",cir.cent.x,cir.cent.y);
            printf("%0.2lf
    ",cir.r);
        }
        return 0;
    }
    

      

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  • 原文地址:https://www.cnblogs.com/jie-dcai/p/3904413.html
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