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  • HDU 2846 Repository(字典树)

      字典树较为复杂的应用,我们在建立字典树的过程中需要把所有的前缀都加进去,还需要加一个id,判断它原先是属于哪个串的.有人说是AC自动机的简化,但是AC自动机我还没有做过.

    #include<iostream>
    #include<string.h>
    #include<cstdio>
    using namespace std;
    char a[22],b[22];
    struct Node
    {
        int id,num;
        Node *sons[26];
        Node()
        {
            id = -1,num = 0;
            for(int j = 0; j < 26; j++)
                sons[j] = NULL;
        }
    };
    Node *root;
    Node *now,*Next;
    void Build(char *str,int len,int nowid)
    {
        now = root;
        for(int i = 0; i < len; i++)
        {
            int m = str[i] - 'a';
            if(now->sons[m] == NULL)
            {
                Next = new Node;
                Next->id = nowid;
                Next->num = 1;
                now->sons[m] = Next;
                now = Next;
            }
            else
            {
                now = now->sons[m];
                if(now->id != nowid)
                {
                    now->id = nowid;
                    now->num++;
                }
            }
        }
    }
    int Find(char *str,int len)
    {
        now = root;
        for(int i = 0; i < len; i++)
        {
            int m = str[i] - 'a';
            if(now->sons[m] == NULL) return 0;
            now = now->sons[m];
        }
        return now->num;
    }
    void del(Node *root)
    {
        for(int i = 0; i < 26; i++)
        {
            if(root->sons[i] != NULL)
                del(root->sons[i]);
        }
        delete root;
    }
    int main()
    {
        int n,m;
        while(~scanf("%d",&n))
        {
            root = new Node;
            for(int i = 1; i <= n; i++)
            {
                scanf("%s",a);
                int lena = strlen(a);
                for(int j = 0; j < lena; j++)
                    Build(a+j,lena-j,i);
            }
            scanf("%d",&m);
            for(int i = 1; i <= m; i++)
            {
                scanf("%s",b);
                int lenb = strlen(b);
                printf("%d
    ",Find(b,lenb));
            }
            del(root);
        }
        return 0;
    }
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  • 原文地址:https://www.cnblogs.com/jifahu/p/5449489.html
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