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  • python作业(二)

    # print(5 < 4 or 3)   #3
    # print(2 > 1 or 6) #t
    # print(3 >1 and 0) #0
    # #计算 1 - 2 + 3 ... + 99 中除了88以外所有数的总和

    # i = 1
    # sum = 0
    # while i < 100:
    # if i != 88:
    # if i % 2 > 0:
    # sum += i
    # else:
    # sum -= i
    # i += 1
    # print(sum)

    ##户登陆(三次输错机会)且每次输错误时显示剩余错误次数(提示:使字符串格式化)
    # i = 1
    # uname = "jinyu"
    # pd = "123456"
    # while i < 4:
    # unamei = input("please input name")
    # pdi = input("please inptu pd")
    # if unamei == uname and pdi == pd:
    # print("bingo")
    # break
    # else:
    # print("fales you have %d" %(3 - i))
    # i += 1
    # else:print("pppppp")

    # #计算 1 - 2 + 3 ... -99 中除了88意外所有数的总和
    i = 0
    sum = 0
    j = -1
    while i < 99:
    i += 1
    if i == 88:
    continue
    else:
    j = -j
    sum = sum + i * j
    print(sum)

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  • 原文地址:https://www.cnblogs.com/jinyudsc/p/9626545.html
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