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  • 简单的struts2框架(一)

    struts2-blank.war,放到tomcat的webapps下,重新启动会部署,在部署后,会产生practice_struts2

    下载地址:http://pan.baidu.com/s/1jGKcvgq

    一:加载Struts2类库
    struts2-core-2.3.16.3.jar 框架的核心类库
    xwork-core-2.3.16.3.jar XWork类库,构架基础
    ognl-3.0.6.jar 使用的一种表达式语言类库
    freemarker-2.3.19.jar 标签模板使用类库
    commons-fileupload-1.3.1.jar 文件上传依赖包
    commons-io-2.2.jar
    javassist-3.11.0.GA.jar
    commons-lang3-3.1.jar

    二:配置web.xml
    (将全部请求定位到指定的Struts2过滤器中)

     1 <filter>
     2     <filter-name>struts2</filter-name>
     3     <filter-class>org.apache.struts2.dispatcher.ng.filter.StrutsPrepareAndExecuteFilter</filter-
     4 
     5 class>    
     6 </filter>
     7 <filter-mapping>
     8     <filter-name>struts2</filter-name>
     9     <url-pattern>/*</url-pattern>
    10 </filter-mapping>

    (<url-pattern>/*</url-pattern>是所有的都走filter-class.)
    (<url-pattern>*.action</url-pattern>是.action的才走filter-class.)

    三:开发控制层
    struts.xml的配置

     1 <?xml version="1.0" encoding="UTF-8"?>
     2 <!DOCTYPE struts PUBLIC
     3     "-//Apache Software Foundation//DTD Struts Configuration 2.3//EN"
     4     "http://struts.apache.org/dtds/struts-2.3.dtd">
     5 <struts>
     6 
     7     <package name="default" namespace="/user" extends="struts-default">
     8         <action name="loginAction" class="struts.loginAction">
     9             <result name="success" type="dispatcher">/user/Success.jsp</result>
    10             <result name="error" type="dispatcher">/user/Error.jsp</result>
    11         </action>
    12         
    13     </package>
    14     
    15 </struts>    

    (<package name="default" namespace="/user" extends="struts-default">
    namespace是jsp所在的包名,extends是继承struts-default.xml的方法)
    (<result name="success" type="dispatcher">/user/Success.jsp</result>)
    接收返回的result的值,判断显示哪个jsp

    四:显示层:UserLogin.jsp:

    1 <form action="/practice_struts2/user/loginAction.action" method="post">
    2     
    3         用户名:<input name="username" type="text"><br/>
    4         密    码:<input name="userpwd" type="password"><br/>
    5         <input type="submit" value="登录"/><input type="reset" value="重置"/>
    6         
    7     </form>

    (<form action="/practice_struts2/user/loginAction.action" method="post">)
    action里是/工程名+namespace+struts.xml里action的name,调用相对应的class

    五:业务处理:

     1 package struts;
     2 
     3 import servlet.UserServlet;
     4 import com.opensymphony.xwork2.ActionSupport;
     5 public class loginAction extends ActionSupport {
     6     
     7     private String username;
     8     private String userpwd;    
     9     private UserServlet userservlet=new UserServlet();
    10     public String execute(){
    11         //业务功能的调用
    12         System.out.println(username+userpwd);
    13         boolean ret=userservlet.login(username, userpwd);
    14         if(ret){
    15             //呈现数据,给struts.xml的result
    16             return "success";
    17         }else{
    18             return "error";
    19         }        
    20     }
    21 
    22     public String getUsername() {
    23         return username;
    24     }
    25     public void setUsername(String username) {
    26         this.username = username;
    27     }
    28     public String getUserpwd() {
    29         return userpwd;
    30     }
    31     public void setUserpwd(String userpwd) {
    32         this.userpwd = userpwd;
    33     }    
    34 }
     1 package servlet;
     2 public class UserServlet {    
     3     public boolean login(String username,String userpwd){
     4         if(username.equals("111")&&userpwd.equals("111")){
     5             return true;
     6         }else{
     7             return false;
     8         }
     9     }
    10 }
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  • 原文地址:https://www.cnblogs.com/jiuqing/p/4042969.html
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