zoukankan      html  css  js  c++  java
  • ACM Bee

    In Africa there is a very special species of bee. Every year, the female bees of such species give birth to one male bee, while the male bees give birth to one male bee and one female bee, and then they die! Now scientists have accidentally found one “magical female bee” of such special species to the effect that she is immortal, but still able to give birth once a year as all the other female bees. The scientists would like to know how many bees there will be after N years. Please write a program that helps them find the number of male bees and the total number of all bees after N years. Input Each line of input contains an integer N (≥ 0). Input ends with a case where N = −1. (This case should NOT be processed.) Output Each line of output should have two numbers, the first one being the number of male bees after N years, and the second one being the total number of bees after N years. (The two numbers will not exceed 232.) Sample Input

    1

    3

    -1

    Sample Output

    1 2

    4 7

    参考博客:

    http://blog.csdn.net/tower13/article/details/51064619

    /*
        参考:
         http://blog.csdn.net/tower13/article/details/51064619    
    */
    #include<stdio.h>
    int main()
    {
        long long int n;
        while(~scanf("%lld",&n)&&n != -1){
            long long int sum = 1 ,w = 1,m = 0,temp1;
            for(long long int i = 1;i <= n; i++)
            {
                temp1 = w;
                w = m+1;           //雌蜂数量 = 上一年的雄蜂+1    
                m = temp1 + m;  //雄蜂数量 =  上一年的雌蜂+雄蜂
                    
            } 
            printf("%lld %lld
    ",m,w+m);        
    }    
    return 0;
    }
  • 相关阅读:
    Java并发编程(二)线程任务的中断(interrupt)
    Java并发编程(一) 两种实现多线程的方法(Thread,Runnable)
    青蛙跳台阶(Fibonacci数列)
    旋转数组的最小值
    用两个栈实现队列
    重建二叉树
    二维数组中的查找
    Lab 3-1
    Lab 1-4
    Lab 1-3
  • 原文地址:https://www.cnblogs.com/jj81/p/7197722.html
Copyright © 2011-2022 走看看